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nordsb [41]
3 years ago
11

6. Stella saved $81. Her sister saved $9. Stella saved Sortimes as much as her sister.

Mathematics
1 answer:
Furkat [3]3 years ago
4 0
All you do is subtract 81 from 9 and it’s 72 from what I understood from your question
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Brainliest answer to the one who will be first and correctly.
inessss [21]

Answer:

21

Step-by-step explanation:

dog = 35/85 = x/51

=> x = 35 x 51 / 85 = 7 x 51 / 17 = 21

4 0
3 years ago
Read 2 more answers
What is the value of (-3/4)^-4
blsea [12.9K]

Answer:

256/81

Step-by-step explanation:

According to the formula:

a^{-b}=1/a^{b}

Using the above formula to solve the question, we perform following steps:

(-3/4)^{-4}=1/(-3/4)^{4}

                    =4^{4}/(-3)^{4}

                    =(4*4*4*4)/(-3*-3*-3*-3)

                     =256/81 which is the required answer.

8 0
3 years ago
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To compound 50% solution in which proportion must 95% sol and 30% sol be mixed to make
Varvara68 [4.7K]

Answer:

4/9

Step-by-step explanation:

Let the amount of 95% sol = a ml and

the amount of 30% sol = b ml.

So, the total amount of the compound=a+b=500 ml

As the compound is 50% solution, so

95% of a + 30% of b= 50% of (a+b)

(95/100)a+(30/100)b=(50/100)(a+b) [from equation (i)]

95a + 30b = 50(a+b)

95(a/b)+30 = 50(a+b)/b [dividing both sides by b]

95(a/b)+30 = 50(a/b+1)

95(a/b)+30 = 50(a/b)+50

95(a/b)-50(a/b)=50-30

45(a/b)=20

a/b=20/45

a/b=4/9

Therefore, a:b=4:9

As a+b= 500 ml, so the amount of 95% sol = \frac {500}{13}\times 4=\frac{2000}{13}=153.85 ml

and the amount of 95% sol = \frac {500}{13}\times 9=\frac{4500}{13}=346.15 ml

Hence, the proportion of 95% sol and 30% sol to make a compound of 50% sol must be 4/9.

3 0
3 years ago
Which is the mixed numebr for three and five-eights? <br><br> PLEASE SHOW UR EXPLATION
Elza [17]

Answer:

3 5/8

Step-by-step explanation:

it's 3 5/8 because there are 3 wholes and 5/8 fractions

4 0
3 years ago
The square root of -8 times the square root of -40
Ksju [112]
The answer is:  " -8 √5 " .
_________________________________________________________
Note:
_________________________________________________________

√-8 *√-40 = i√8 * i√40 ;  {since: "i" refers to the imaginary number; " √-1 " } ;

= i² * √8 *√40 ;
___________________________

Note: 

"√8 * √40 = ? " ;

↔  " √8 = √4 √2 = 2√2 " ;

      "√40 = √4 √10 = 2√10" ;

→ "√8 √40 = 2 * 2 * √2 * √10 ;

                  = 4 * √(2*10)  ;

                  = 4 √20 ; 

 →  " √20 = √4 √5 = 2√5 ; 

 → 4 √20 = 4 * 2 * √5  

= 8 √5 ;

 → i² * 8 √5 ;

↔ 8 i² √5 ;

Note:  " i² = -1" ; 

→ 8(-1) * √5 ; 

= -8 √5 .
_____________________________________________________


6 0
3 years ago
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