Answer:
When t=2.1753 & t=.5746 , h=27
Don't worry, I got you. Also, my calculator does too.
We set h equal to 27, because we want the height to be 27 when we solve for t.
That leaves us with:
27 = 7 + 44t - 16t^2
Simplify like terms,
20 = 44t - 16t^2
Move 20 onto the right side, so we can use quadratic equation
44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20
Using quadratic, you get
t=2.1753 & t=.5746
<u>poster confirmed : "It’s t=2.18 and t=0.57"</u>
It would be
3.5 × 10⁻³ kg.
The decimal point must be moved 3 places to the right in order to have it behind the first non-zero digit; this gives us the exponent of 3, and since we are moving the decimal to the right, it is a negative exponent.
Answer:
A. It would become a different atom.
C. Its charge would increase by 1
Step-by-step explanation:
Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.
