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kipiarov [429]
2 years ago
11

Scenarios of unit rates

Mathematics
1 answer:
Masja [62]2 years ago
8 0
Price per unit (gram, pound, ounce gallon)

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Find the common difference for the given sequence<br> 1.2, 1.85, 2.5, 3.15, ...
Kay [80]

Answer:

c)0.65

Step-by-step explanation:

7 0
3 years ago
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Sara was thinking of a number. Sara halves the number and gets an answer of 38.5. Form an equation with x for the information
lbvjy [14]

Answer:The equation wth x in the information can be written as

1/2 x = 38.5 , Upon solving, the number = 77

Step-by-step explanation:

Let the number Sara was thinking about be x

halving the number to get an answer = 38.5 can be expressed as

 1/2 X = 38.5

The equation with x in the information can be written as

1/2 x = 38.5

solving it becomes

1/2 x= 38.5

x = 38.5 x 2

x=77

The number Sara was thinking about = 77

4 0
3 years ago
-5(2 × -6) inverse operation
Gekata [30.6K]

Answer:

60

Step-by-step explanation:

-5(2×-6)

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60

It should be correct

5 0
2 years ago
What is the tens fact for 14-6
sasho [114]
14-6=8 and its 10 x1
4 0
3 years ago
Find a polynomial P(x) with real coefficients having a degree 4, leading coefficient 4, and zeros 3-i and 4i.
Alisiya [41]

now, this polynomial has roots of 3-i and 4i, namely 3 - i and 0 + 4i.

let's bear in mind that a complex root never comes all by her lonesome, her sibling is always with her, the conjugate, so if 3 - i is there, 3 + i is also coming along, likewise if 0 + 4i is there, her sibling 0 - 4i is also there.

\bf \begin{cases} x=3-i\implies &x-3+i=0\\ x=3+i\implies &x-3-i=0\\ x=4i\implies &x-4i=0\\ x=-4i\implies &x+4i=0 \end{cases}\\\\[-0.35em] ~\dotfill\\\\ (x-3+i)(x-3-i)(x-4i)(x+4i)=\stackrel{y}{0} \\[2em] \underset{\textit{difference of squares}}{[(x-3)+i][(x-3)-i]}\underset{\textit{difference of squares}}{[x-4i][x+4i]}=0

\bf [(x-3)^2-i^2][x^2-(4i)^2]=y\implies [(x-3)^2-(-1)][x^2-(4^2i^2)]=0 \\[2em] [(x-3)^2-(-1)][x^2-(16(-1))]=0\implies [(x-3)^2+1][x^2+16]=0 \\[2em] [(x^2-6x+9)+1][x^2+16]=y\implies (x^2-6x+10)(x^2+16)=0 \\\\\\ x^4-6x^3+10x^2+16x^2-96x+160=0 \\\\\\ x^4-6x^3+26x^2-96x+160=0 \\\\\\ \stackrel{\textit{multiplying both sides by 4}}{4(x^4-6x^3+26x^2-96x+160)=4(0)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x^4-24x^3+104x^2-384x+640=y~\hfill

3 0
3 years ago
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