Question

A line passes through the points (-3, 14) and (-1, 16). What is its equation in slope-intercept form?​

Answer 1

Answer:

y = 6x + 22

General Formulas and Concepts:

Pre-Alg

• Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Slope-Intercept Form: y = mx + b

• m - slope

• b - y-intercept

Step-by-step explanation:

Step 1: Define

Point (-3, 14)

Point (-1, 16)

Step 2: Find slope m

1. Substitute:                    $m=\frac{16-14}{-1+3}$
2. Subtract/Add:               $m=\frac{12}{2}$
3. Divide:                           $m=6$

Step 3: Find y-intercept b

1. Define:                    y = 6x + b
2. Substitute:              16 = 6(-1) + b
3. Multiply:                  16 = -6 + b
4. Isolate b:                 22 = b
5. Rewrite:                   b = 22

Step 4: Write linear equation

y = 6x + 22