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Neko [114]
3 years ago
11

A line passes through the points (-3, 14) and (-1, 16). What is its equation in slope-intercept form?​

Mathematics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

y = 6x + 22

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-3, 14)

Point (-1, 16)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{16-14}{-1+3}
  2. Subtract/Add:               m=\frac{12}{2}
  3. Divide:                           m=6

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = 6x + b
  2. Substitute:              16 = 6(-1) + b
  3. Multiply:                  16 = -6 + b
  4. Isolate <em>b</em>:                 22 = b
  5. Rewrite:                   b = 22

<u>Step 4: Write linear equation</u>

y = 6x + 22

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Answer:

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Step-by-step explanation:

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Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

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9). Following the same rule as above,

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