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Arturiano [62]
3 years ago
9

ASAP PLEASE HELP!! I KEEP ON TRYING BUT IM DOING SOMETHING WRONG SOMEONE PLEASE HELP!!!!

Mathematics
1 answer:
djyliett [7]3 years ago
3 0
The answer is A

if you add them all together, there are 15 employees, and only 5 have at least 10 years of experience. 5/15 simplifies to 1/3
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Number Lines / Algebra. Can anyone please tell me to answers to all of these number lines below. Thank you!!
iren [92.7K]
I will do the first-two lines only.

-4 -3 -2 -1 0 1 2 3 4 5 6

Next line below.

-5 -4 -3 -2 -1 0 1 2 3 4 5

Do the rest.
5 0
3 years ago
State the excluded values for each? 70v^2/100v
sleet_krkn [62]
Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense

6 0
4 years ago
Ryan's brother works in a shoe store. He earns $12 per hour. The store offers him a raise — a 5% increase per hour. After the ra
TEA [102]

Answer:

$12.60

Step-by-step explanation:

12x.05 = .6 then .6+12 is 12.6

sorry if this is wrong lol

8 0
2 years ago
I need this answer hurry please
Brums [2.3K]

Answer:

21 ft²

Step-by-step explanation:

3*5 + 2*3 = 21

4 0
3 years ago
find continued product of (x+y) (x-y) (<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}"
leonid [27]

Answer:

\large\boxed{(x+y)(x-y)(x^2+y^2)(x^4+y^4)=x^8-y^8}

Step-by-step explanation:

(x+y)(x-y)(x^2+y^2)(x^4+y^4)\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\qquad(*)\\\\=\underbrace{(x+y)(x-y)}_{(*)}(x^2+y^2)(x^4+y^4)\\\\=\underbrace{(x^2-y^2)(x^2+y^2)}_{(*)}(x^4+y^4)\\\\=\left((x^2)^2-(y^2)^2\right)(x^4+y^4)\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\underbrace{(x^4-y^4)(x^4+y^4)}_{(*)}\\\\=\left(x^4\right)^2-\left(y^4\right)^2=x^8-y^8

7 0
4 years ago
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