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zubka84 [21]
3 years ago
12

H/6 -1 = -3 Please help guys!

Mathematics
2 answers:
frozen [14]3 years ago
7 0

Answer:

H = -12

Step-by-step explanation:

H/6 -1 = -3

H/6 = -3 + 1

H/6 = -2

H= 6 × -2

H = -12

Gennadij [26K]3 years ago
4 0

Answer:

h=-12

Step-by-step explanation:

h/6-1=-3

add 0ne to -3 since it's the opposite of -1

h/6=-2

multiply by 6/1 since it's the opposite of 1/6

h=-12

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When any number is multiplied by 6 adn the digits of the answer are added?
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The result is always divisible by 3.
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P(a)=0.50 p(b)=0.30 and p(a and b)=0.15 what is p(a or b)
Softa [21]

Answer:

Option C is correct

P(A or B) = 0.65

Step-by-step explanation:

<u>Given: </u>

P(A) =0.5

P(B)=0.30

P(A and B) =0.15

( The probability of the happening of both independent events will be there product) P( A and B ) =P(A).P(B)

<u>Solution:</u>

To find the probability  of the Happening of event A either event B  we will use the following formula

P(A or B) = P(A) + P(B)-P(A and B)

                  = 0.5 + 0.3 - 0.15

                  =0.65

6 0
4 years ago
Read 2 more answers
Chris has 150 cookies to sell each cookie is covered with one topping 1 /5 of cookie are covered with coconut 1/3 of the cookie
Elan Coil [88]

Answer:

1/6 or 25

Step-by-step explanation:

1/3=10/30

3/10=9/30

1/5=6/30

together is 25/30, which leaves the rest, 5/30 or 1/6 or 25 cookies.

3 0
4 years ago
The line with equation 4b + a = 0 coincides with the terminal side of an angle x in standard position in Quadrant IV.
nignag [31]
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8 0
3 years ago
Read 2 more answers
A. What is the probability that this couple spends 45 dollars or more?
guapka [62]

Using the probability table, it is found that:

  • a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more.  
  • b) The expected amount the couple actually has to pay is $36.85.

Item a:

To find the probabilities involving the total cost, we have to <u>add the variables X and Y</u> from the table, then:

P(X = 30) = P(X = 15|Y = 15) = 0.2

P(X = 35) = P(X = 15|Y = 20) + P(X = 20|Y = 15) = 0.15 + 0.15 = 0.3

P(X = 40) = P(X = 15|Y = 25) + P(X = 20|Y = 20) + P(X = 25|Y = 15) = 0.05 + 0.15 + 0.05 = 0.25

P(X = 45) = P(X = 20|Y = 25) + P(X = 25|Y = 20) = 0.1 + 0.1 = 0.2

P(X = 50) = P(X = 25|Y = 25) = 0.05

The probability involving <u>values of 45 or more</u> is:

P(X \geq 45) = P(X = 45) + P(X = 50) = 0.2 + 0.05 = 0.25

0.25 = 25% probability that this couple spends 45 dollars or more.

Item b:

For a <em>discrete distribution</em>, the expected value is the <u>sum of each outcome multiplied by it's respective probability</u>, hence, involving the 10% discount for prices above $45:

E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85

The expected amount the couple actually has to pay is $36.85

A similar problem is given at brainly.com/question/25782059

8 0
2 years ago
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