Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)

The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!
Answer:
Domain: 
Range: ![[0,4]](https://tex.z-dn.net/?f=%5B0%2C4%5D)
Step-by-step explanation:
<u>Domain</u>
We can see that the piecewise function starts at x=-2, which is included, and ends at x=1, which isn't included. To represent the x-values that lie in between these two endpoints, you would write
. Brackets show that one endpoint is included while parentheses show that one endpoint isn't included.
<u>Range</u>
Following this logic, the range has its y-values go from 0 to 4 with both endpoints included if you were to trace the function. Thus, your range would be
.
Answer:
7 / 16
Step-by-step explanation:
Sample space is attached below :
Theoretical Probability of any event A
P(A) = (number of required outcome / Total number of possible outcomes)
Required outcome = sum greater than 7 = 14
Total number of possible outcomes = 32
P(sum greater than 7) = 14 / 32
P(sum greater than 7) = 7 / 16
The answer is 30720
A = P * rⁿ
A - the final population
r - the growth rate
P - the initial number of bacteria
n - the number of hours
We know:
A = ?
r = 2 (it doubles)
P = 15
n = 12
After 11 hours
A(11) = 15 * 2¹²
A(11) = 15 * 2048
A(11) = 30720
After 12 hours
A(12) = 15 * 2¹²
A(12) = 15 * 4096
A(12) = 61440
<span>How many bacteria are grown during the 12th hour?
A(12) - A(11) = 61440 - 30720 = 30720</span>