Express x from first equation:
x = y - z - 1
Replace x with found value in second equation and solve it:
y - z - 1 + y + z = 5
2y - 1 = 5
2y = 6
y = 3
Replace x with found value in third equation:
y - z - 1 + y - z = -3
Replace y with found value in this equation and solve it:
3 - z -1 + 3 - z = -3
-2z = -3 - 3 + 1 - 3
-2z = -8
2z = 8
z = 4
Find x by replacing y and z in first equation and solving it:
x = y - z - 1
x = 3 - 4 - 1 = -2
So x = -2, y = 3, z = 4
Equivalent ratios
....................................................
Answer:
A and B
Step-by-step explanation:
The "zeros" of the quadratic equation simply refers to what x equals when q(x) = 0.
Set the equation equal to zero as so: 0 = x^2 - 9, and solve!
9 = x^2
+/- 3 = x, when q(x) = 0.
This means that the two points you are trying to find are (-3, 0) and (3, 0)!
Let's simplify step-by-step.
<span><span>18x</span>+6
</span>There are no like terms.
Answer:
<span>=<span><span>18x</span>+<span>6
or
</span></span></span>Factor <span><span>18x</span>+6
</span><span><span>18x</span>+6
</span><span>=<span>6<span>(<span><span>3x</span>+1</span>)
</span></span></span>Answer:
<span>6<span>(<span><span>3x</span>+1</span><span>)</span></span></span>
The amount of ways would be :
9! / (9-3) !
= 9 ! / 6 !
= 9 x 8 x 7
= 504
The answer is option B,
hope this helps