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3 years ago

The formula for finding the perimeter of a rectangle with length, l, and width, w, is P = 2l + 2w.

2 answers:

7 0

P1=2(l+w)---->(equation 1)
after the length and the width are doubled
p2=2(2l+2w)
we will take 2 common factor out of the bracket
p2=2(2(l+w))
then from equation1
p2=2p1
then the answer is the choice number c

creativ13 [48]3 years ago

6 0

The perimeter will grow by a factor of 2, so C is the correct answer.

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dolphi86 [110]

Answer:

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3 years ago

May someone help me with these 2 again

cestrela7 [59]

Answer:

1. 180

2. x = 31

Step-by-step explanation:

1. the sum of the interior angles of every triangle is always 180

2. using what we know from problem 1, we can create an equation:

x + 10 + 2x - 5 + 2x + 20 = 180

add like terms: 5x + 25 = 180

subtract 25 from both sides: 5x = 155

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3 years ago

Dan bought one package if blackberries for 3 dollars/euros. How many packages can Darryl buy if he has 15 dollars/euros?

myrzilka [38]

Answer:

Dan can buy 5 bags for 15 dollars

Step-by-step explanation:

divide 15 and 3 it will equal 5

6 0

3 years ago

Read 2 more answers

If the dimensions of the following cylinder are quadrupled, what will be the volume of the new similar cylinder?

Alik [6]

Answer: First option is correct.

Explanation:

Since we have given that

Radius = 11 inches

Height = 14 inches

Now, according to question, we have mentioned that all the dimensions of the cylinder is to be quadrupled i.e. four times.

Then,

Radius is given by

$4\times 11=44 inches$

Height is given by

$14\times 4=56\ inches$

As we know the formula for " Volume of cylinder ":

$V=\pi r^2h\\\\V=3.14\times 44\times 44\times 56=340426.24\ in^3$

Hence, our volume of new similar cylinder is 340426.24 cubic in.

Therefore, First option is correct.

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3 years ago

Read 2 more answers

A point charge q1 = 3.30nC is located on the x-axis at x= 1.90m , and a second point charge q2= -6.40 nC is on the y-axis at y=

Dahasolnce [82]

Answer:

Step-by-step explanation:

charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m

here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,

$\phi =\frac{q}{\epsilon _{0}}$

where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.

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3 years ago