Answer:
the first one.
Step-by-step explanation:
The pattern is plus 10 for each time
Formula recursive
A_n = A_n -1 + 10
So the next term is 5th
A_5 = A_5 -1 + 10
A_5-1 = A_4 +10
5th = 6+10 = 16
I think you can do it for the next 2 terms.
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
6.50
Step-by-step explanation:
15.75-9.25=6.5
In the recursive rule, there's a variable where you plug in the number of times you need the sequence to repeat, but you don't put 1 in that slot because there's another formula/rule you use to find that answer (I can't remember the name of the other rule right now I apologize I hope this makes sense)
