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Lady_Fox [76]
3 years ago
11

Write the equation of a line that is perpendicular to y=-2x/7+9 and that passes through the point (4,−6)

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer:

  y = (7/2)x -20

Step-by-step explanation:

The given line is in slope-intercept form, so you can read its slope from the equation.

  y = mx + b . . . . . m is the slope; b is the y-intercept

  y = -(2/7)x + 9 . . . . . . has slope -2/7

The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...

  m = -1/(-2/7) = 7/2

We can use this and the given point to write the equation in point-slope form.

  y = m(x -h) +k . . . . . . line with slope m through point (h, k)

We have m = 7/2, (h, k) = (4, -6) so the equation is ...

  y = (7/2)(x -4) -6

  y = (7/2)x -20

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