Write the equation of a line that is perpendicular to y=-2x/7+9 and that passes through the point (4,−6)
1 answer:
Answer:
y = (7/2)x -20
Step-by-step explanation:
The given line is in slope-intercept form, so you can read its slope from the equation.
y = mx + b . . . . . m is the slope; b is the y-intercept
y = -(2/7)x + 9 . . . . . . has slope -2/7
The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...
m = -1/(-2/7) = 7/2
We can use this and the given point to write the equation in point-slope form.
y = m(x -h) +k . . . . . . line with slope m through point (h, k)
We have m = 7/2, (h, k) = (4, -6) so the equation is ...
y = (7/2)(x -4) -6
y = (7/2)x -20
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