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3 years ago

14

What is 1 plus 1 minus 1 times 1 times 1 subtract 1 plus 1 times 1 divided by 1 times 1 divided by 1 subtract 1 plus 1 plus 1 di

vided by 1?
Answer quick pls

2 answers:

Alexeev081 [22]3 years ago

7 0

The CORRECT answer is <u>2</u>.

(I feel like that's obvious) :/

Lesechka [4]3 years ago

3 0

Answer:

zero

Step-by-step explanation:

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Which is the intersection of the sets {0, 1, 5, 7, 8} and {0,5,7,9}?

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Answer:

Step-by-step explanation:

Intersection set will contain the data that are found in both the sets

A = { 0 , 1 ,5 ,7,8}

B= {0,5,7,9}

A ∩ B = {0,5,7}

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State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

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2 years ago

The function f is defined by f(x)=3x+2.<br> Find f(a-4).

Solnce55 [7]

Answer:

3a-10

Step-by-step explanation:

<h2>MAYBE IT HELPS</h2>

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A line passes through (−1, 5) and (1, 3)

ikadub [295]

I hope this helps you

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