The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
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It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
Answer:
Step-by-step explanation:
<h3><em>The Answer is B, This is the answer beacuse R and S is true. There are some methonds you can do to help you solve any questions like these in the future. I hope this well help.</em></h3>
Answer:
72
Step-by-step explanation:
3(20+4)=a0
60+12=a0
72=a0
im not quite sure what you want. I solved for a0. Plz tell me if this is correct. If its not, tell me what u need, then I will solve it for you.
Answer:
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Answer:
Here you go
Step-by-step explanation:
x=0,-4
