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juin [17]
2 years ago
14

What is 1 plus 1 minus 1 times 1 times 1 subtract 1 plus 1 times 1 divided by 1 times 1 divided by 1 subtract 1 plus 1 plus 1 di

vided by 1?
Answer quick pls
Mathematics
2 answers:
Alexeev081 [22]2 years ago
7 0

The CORRECT answer is <u>2</u>.

(I feel like that's obvious) :/

Lesechka [4]2 years ago
3 0

Answer:

zero

Step-by-step explanation:

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What is the value of x in the equation −x = 4 − 3x + 6?<br><br> 5<br> 10<br> −5<br> −10
ddd [48]
Combine like terms

-x = 4 + 6 - 3x
-x = 10 - 3x

Isolate the x, add 3x to both sides

-x (+3x) = 10 - 3x (+3x)

-x + 3x = 10

Simplify. Combine like terms

-x + 3x = 10

2x = 10

Isolate the x, divide 2 from both sides

2x/2 = 10/2

x = 10/2

x = 5

x = 5, or A is your answer

hope this helps
8 0
3 years ago
Read 2 more answers
X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of
sladkih [1.3K]
X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125

x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989

So we verified y = 5
3 0
3 years ago
What is the general form of the equation for the given circle?
Westkost [7]
I think the answer is B or C
7 0
3 years ago
Please answer even if there is already 1, last time i asked this i put a lot of points and a bot took them and i dont have time
Alekssandra [29.7K]

Answer:

The answer would be A

Step-by-step explanation:

a. the pumpkins maximum height is 204.06 feet and it hits the ground after 7.01 seconds.

7 0
2 years ago
What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
2 years ago
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