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3 years ago

Which of the following has a solution set of {x | x = 0}?

Mathematics

2 answers:

Burka [1]3 years ago

8 0

It is B
(x+1<1)this mark(x+1>1)

Olenka [21]3 years ago

3 0

B, since by subtracting one from both sides of both equations, you get x <= 0 and x >= 0. That is only true for x = 0.

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Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

<u>Given quadratic equation</u>:

$5x^2-6x-2=0$

<u>Define the variables</u>:

a = 5
b = -6
c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

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brainly.com/question/27953354

3 0

1 year ago

Read 2 more answers

Most __________ signs are rectangular, with the longer dimension vertical, and have a white background.

Furkat [3]

Answer:

Regulatory

Step-by-step explanation:

the rectangular sign with longer vertical dimension and have white background are called regulatory signs.

regulatory signs are those signals which are used to indicate or reinforce traffic laws.

these regulatory sign informs the driver and tell them to apply the traffic law at certain required places.

6 0

3 years ago

subtracting 1 to the product of 5 and x gives the same value as adding 10 to the product of 3 and x. what value of x makes the s

STatiana [176]

Answer:

true statement that makes

7 0

3 years ago

URGENTLY NEED THIS ASAP PLZ TYSM

Kazeer [188]

Answer:

fifth option

Step-by-step explanation:

Given

- 2(x - 5) ≤ 6x + 18 ← distribute left side

- 2x + 10 ≤ 6x + 18 ( subtract 6x from both sides )

- 8x + 10 ≤ 18 ( subtract 10 from both sides )

- 8x ≤ 8

Divide both sides by - 8, reversing the sign as a result of dividing by a negative quantity, thus

x ≥ - 1

3 0

3 years ago

find the three consecutive odd integers such that the sum of twice the first and three times the second is 67 more than twice th

Elenna [48]

Answer:

23, 25, 27

Step-by-step explanation:

It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.

<h3>setup</h3>

Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...

2(x -2) +3x = 67 +2(x +2)

<h3>solution</h3>

5x -4 = 2x +71 . . . . . simplify

3x = 75 . . . . . . . . add 4-2x

x = 25 . . . . . . . divide by 3

The three integers are 23, 25, 27.

4 0

2 years ago