Answer:
y=1, x=1
Step-by-step explanation:
you put the y variable in the equation 4x-5y=9
and you get that y=1
then you add the y=1 in the forst equatiom amd you get that x=1 as well
The rest of the question is as following:
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<span>1) Evan’s graph is a vertical translation of f(x) = x2.
2) Victor’s graph is a vertical translation of f(x) = x2.
3) Evan’s graph moved 4 units from f(x) = x2 in a positive direction.
4) Victor’s graph moved 4 units from f(x) = x2 in a positive direction.
5) Evan’s graph has a y-intercept of 4.
6) Victor’s graph has a y-intercept of 4.
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Solution :
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The functions plotted by Evan and Victor forms a parabola as shown in attached figure.
The correct answers from the choices are:
</span><span>1) Evan’s graph is a vertical translation of f(x) = x2.
</span>
3) Evan’s graph moved 4 units from f(x) = x2 in a positive direction.
<span><span><span>5) Evan’s graph has a y-intercept of 4.
</span></span>
</span>
The graph of the function f(x)=3(2)^x -4 passes through the points (0,-1), (1,2), (2,8) and (3,20)
<h3>What are exponential functions?</h3>
When the expression of function is such that it involves the input to be present as exponent (power) of some constant, then such function is called exponential function.
here usual form is specified below. They are written in several such equivalent forms.
The equation of the function is given as:
![f(x)=3(2)^x -4](https://tex.z-dn.net/?f=f%28x%29%3D3%282%29%5Ex%20-4)
Set x = 0, 1, 2 and 3
![f(0)=3(2)^0 -4 = -1\\f(1) = 3(2)^1 - 4 = 2\\f(2) = 3(2)^2- 4 = 8\\\\f(3) = 3(2)^3 - 4 = 20](https://tex.z-dn.net/?f=f%280%29%3D3%282%29%5E0%20-4%20%3D%20-1%5C%5Cf%281%29%20%3D%203%282%29%5E1%20-%204%20%3D%202%5C%5Cf%282%29%20%3D%203%282%29%5E2-%204%20%3D%208%5C%5C%5C%5Cf%283%29%20%3D%203%282%29%5E3%20-%204%20%3D%2020)
This means that the graph of the function f(x) = 3(2)^x -4 passes through the points (0,-1), (1,2), (2,8) and (3,20).
Read more about exponential graphs at:
brainly.com/question/11832081
#SPJ1
Answer:
= 1728km2
Step-by-step explanation:
From the formula A = PRT/100%
Where; A is final
P is initial
T is time taken
R is the rate
Therefore A = 3600 × (6/100) × 8
= 1728km2