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3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

Andrei [34K]3 years ago

6 0

Answer:

Hello, the answer would be A. ∠2

Step-by-step explanation:

Hope this helps!

Brainliest please.

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System of equations have one solution<br> A always<br> B sometimes<br> C never

77julia77 [94]

C never, there are always different methods to solve a problem but don't forget that the equation always stays the same!

6 0

3 years ago

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What z score separates the top 70% of the normal distribution from the bottom 30%?

melamori03 [73]

Z/70over30................

7 0

2 years ago

An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov

babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using our values for a, b and c,

$x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656$

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0

3 years ago

Express as a trinomial (2x+8)(x-3)

Luden [163]

Answer:

$\huge\boxed{(2x+8)(x-3)=2x^2+2x-24}$

Step-by-step explanation:

$\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x+8)(x-3)=(2x)(x)+(2x)(-3)+(8)(x)+(8)(-3)\\\\=2x^2-6x+8x-24\qquad\text{combine like terms}\\\\=2x^2+(-6x+8x)-24\\\\=2x^2+2x-24$

8 0

3 years ago

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Simplify (5x−2+3x^2)+(4x+3)

Art [367]

Answer:

3x^2 + 9x + 1

3x ( x + 3 ) + 1

Step-by-step explanation:

(5x - 2 +3x^2 ) + (4x + 3 )

To make this a little bit more easier to read, you can remove the parentheses:

5x - 2 + 3x^2 + 4x + 3

Now, write in a way so that the like terms are next to each other:

3x^2 + 5x + 4x - 2 + 3

Now simplify the 'x' terms to get:

3x^2 + 9x - 2 + 3

Now, simplify the integers (the ones with now variables with them) to get:

3x^2 + 9x + 1

If you want, you can factor out the 3x for two of the terms to get :

3x ( x + 3 ) + 1

Therefore, your simplest form can either be 3x^2 + 9x + 1 OR 3x (x + 3 ) + 1

5 0

3 years ago