1. tent
2. in
3. sert
4. ject
5. sert
6. de
Answer:
The correct option is;
∠AQS ≅ ∠BQS when AS = BS
Step-by-step explanation:
Given that AQ is equal to BQ. When AS is drawn congruent to BS, we have;
QS is congruent to SQ by reflective property
Therefore;
The three sides of triangle QAS are congruent to the three sides of triangle QBS, from which we have;
∠AQS and ∠BQS are corresponding angles, therefore;
∠AQS ≅∠BQS because corresponding angles of congruent triangles are also congruent.
Mass of electron:9.109 times 10^-31 kg
mass of proton: 1.673 times 10-27
speed of light=3.0 times 10^8
avogadro's number 6.02 times 10^32
planck's constant: 6.63 times 10^-34
just google chem constants sheet
Answer:
x = 15
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ KLM is an external angle of the triangle, thus
∠ KLM = ∠ JKL + ∠ KJL , substitute values
5x - 7 = x + 20 + 2x + 3
5x - 7 = 3x + 23 ( subtract 3x from both sides )
2x - 7 = 23 ( add 7 to both sides )
2x = 30 ( divide both sides by 2 )
x = 15
