We know that
The Standard Form of a Quadratic Equation<span> looks like this
</span> ax²<span> + bx + c = 0
</span>
we have
<span>x -1 0 1 2 3
y -20 -6 2 4 0
for x=0 y=-6
then
</span> y=ax² + bx + c --------> -6=a*0² + b*0 + c ---------> c=-6
for y=0 x=3
then
y=ax² + bx + c-------> 0=a*3² + b*3 -6---------> 9a+3b=6----> equation 1
for x=2 y=4
then
y=ax² + bx +
c-----> 4=a*2² + b*2 -6-----> 4=4a+2b-6-----> 4a+2b=10---->
a=2.5-0.5b----> equation 2
I substitute 2 in 1
9*[2.5-0.5b]+3b=6------>
22.5-4.5b+3b=6------> 1.5b=16.5------> b=11
a=2.5-0.5*11------>
a=2.5-5.5------> a=-3
The Standard
Form of a Quadratic Equation is
ax² + bx + c
= 0--------> -3x²+11x-6=0
the answer is
-3x²+11x-6=0
See the attached figure
Hello from MrBillDoesMath!
Answer:
13
Discussion:
w - 10 = 3 => add 10 to both sides
w = 3 + 10
w = 13
Thank you,
MrB
Answer:
43°
Step-by-step explanation:
The first thing you should do is make the equation. We should know that the sum of all the angles is 180. So it should look like this...
Combine like terms:
Subtract the 137 on both sides:
That's it the value of v is 43°.
Answer:
.28 = P( not winning)
Step-by-step explanation:
The probability of winning is .72
The 2 possibilitites are winning and not winning. They must total 1
1 = P(winning) +P( not winning)
1 = .72 + P( not winning)
Subtract .72 from each side
1-.72 = P( not winning)
.28 = P( not winning)
Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean
and standard deviation 
, as long as 
and 
.
The proportion estimate and the sample size are given as follows:
p = 0.45, n = 437.
Hence the mean and the standard error are:
The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is <u>2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42</u>.
Hence:
By the Central Limit Theorem:
Z = (0.42 - 0.45)/0.0238
Z = -1.26
Z = -1.26 has a p-value of 0.1038.
2 x 0.1038 = 0.2076.
0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.
More can be learned about the normal distribution at brainly.com/question/28159597
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