Question

Where is the vertex of y=3(x-26)^2+14?

Answer 1

The vertex is (26,14)

Because it’s written in vertex form which y=a(x-h)^2 + k. H is the x for the vertex And h is changed to it’s opposite. So since 26 is negative it would actually be positive 26. While k ls the y of the vertex which is 14 in our case