Answer: e = 17.8
Step-by-step explanation: 14.6 + 3.2
Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
Answer:
My answer is letter A in a graph
A.
is the secant line on the below circle.
<u>Step-by-step explanation:</u>
The intersection of the circle will result in either Tangent or Secant. Secant is a line intersecting a circle at two different point. This concept explains the relation between the circle and line intersecting it.
From the given diagram,
The
and
intersects the circle at the point H and I.
∴ It can also represented that the
and
intersects at a point G.
From the given options
is the secant line that intersects the circle twice.
Answer:
The correct answer is 
Step-by-step explanation: