Ask question

Ask question

All categories

3 years ago

8

A^3+a+a^2+1 2a^2+2ab+ab^2+b^3

1 answer:

Vikentia [17]3 years ago

6 0

$\frac{a^3+a+a^2+1}{a^3+a^2+ab^2+b^2} \cdot \frac{2a^2+2ab+ab^2+b^3}{a^3+a+a^2b+b} =\frac{a(a^2+1)+1(a^2+1)}{a^2(a+1)+b^2(a+1)} \cdot \frac{2a(a+b)+b^2(a+b)}{a(a^2+1)+b(a^2+1)} =\\\\=\frac{(a^2+1)(a+1)}{(a+1)(a^2+b^2)} \cdot \frac{(a+b)(2a+b^2)}{(a^2+1)(a+b)} = \frac{2a+b^2}{a^2+b^2}$

You might be interested in

Which measurements below will not create a right triangle? *

san4es73 [151]

5 inches, 6 inches, and 7 inches does not create one because 5*2 plus 6*2 equal 61 not 49 of 7*

6 0

3 years ago

Find the value of x of this question

mel-nik [20]

<h3><u>Let's</u><u> </u><u>understand</u><u> </u><u>the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°
So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle
So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

8 0

3 years ago

An entertainment firm offers several DJ choices and light shows that range in price based on the rental time period. The DJ's co

alexdok [17]

219+159≤x≤369+309
The answer can then be simplified to
378≤x≤678

8 0

3 years ago

Please help me I will mark u as brainlist

Juliette [100K]

Answer:

What is the question?

3 0

3 years ago

Hi can you help me on #19 I don’t understand the steps can you please write it out in examples. Thank you so much

UNO [17]

Answer:

4800

Step-by-step explanation:

Given the function

y = 75 × $4^{x}$

x is the number of 15 year periods

45 years has 3 15 year periods , thus x = 3

Substitute x = 3 into the function and solve for y

y = 75 × 4³ = 75 × 64 = 4800

There will be 4800 foxes after 45 years

3 0

3 years ago