Answer:
We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Step-by-step explanation:
We are given that in a group of randomly selected adults, 160 identified themselves as executives.
n = 160
Also we are given that 42 of executives preferred trucks.
So the proportion of executives who prefer trucks is given by
p = 42/160
p = 0.2625
We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.
We can use normal distribution for this problem if the following conditions are satisfied.
n×p ≥ 10
160×0.2625 ≥ 10
42 ≥ 10 (satisfied)
n×(1 - p) ≥ 10
160×(1 - 0.2625) ≥ 10
118 ≥ 10 (satisfied)
The required confidence interval is given by

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.
Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96







Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Answer:10 over 13 x
Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2
to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13
factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)
for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x
solution: 800-10 over 13x so your answer would still be
Answer:
The answer to your question is: letter A
Step-by-step explanation:
From the graph we get the points,
P (2,1)
Q (6,8)
Formula
d = √((x2-x1)² + (y2-y1)²)
d = √((6-2)² + (8-1)²)
d = √ (4² + 7²)
d = √ (16 + 49
d = √65 letter A
x = one angle
y = other angle
y = 15+x
complements add to 90 degrees
x+y = 90
substitute for y (15+x)
x + 15+x = 90
combine like terms
2x+ 15 = 90
subtract 15 from each side
2x = 75
divide each side by 2
x = 75/2
x = 37.5
y = x+15
y = 37.5 + 15
y =52.5
The two angles are 37.5 and 52.5