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Lemur [1.5K]
3 years ago
7

Find the volume of a pyramid with a square base, where the perimeter of the base is

Mathematics
1 answer:
Llana [10]3 years ago
4 0

Answer:

The volume of the pyramid is 101.8m³

Step-by-step explanation:

First of all we need to calculate the sides of the square

p = perimeter = 11.8m

s = side

p = s * 4

we replace with the known values

11.8m = s * 4

11.8m / 4 = s

2.95m = s

To calculate the volume of a pyramid we have to use the following formula:

v = volume

w = width = 2.95m

l = length = 2.95m

h = height = 11.7m

v = (w * l * h) / 3

we replace the values that ​​we know        

v = (2.95m * 2.95m * 11.7m) / 3

v = 101.819m³

Round to the nearest tenth

v = 101.819m³  = 101.8m³

The volume of the pyramid is 101.8m³

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Answer:

Its degree can be at least 1970

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for each root of the form √q, where q is not a square, we have a root -√q. Therefore, we need to find, among the numbers below to 1000, how many sqaures there are.

Since √1000 = 31.6, we have a total of 30 squares:

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Answer:

Follows are the solution to the given choices:

Step-by-step explanation:

In choice a:

\to \mu = 100

In choice b:

\to \mu \neq 100

In choice c:

\to \ pop  \ average=100 \\\\ \to \ variance \ of \ pop = 100  \\\\\to pop  \ \  \sigma = \sqrt {(!00)} \\

               = 10

z= \frac{\bar x - \mu}{ \frac{\sigma}{\sqrt(n)}}\\\\

   =\frac{(105-100)}{\frac{10}{ \sqrt(16)}}\\\\=\frac{(5)}{ \frac{10}{4}}\\\\=\frac{5}{ \frac{5}{2}}\\\\= \frac{10}{5}\\\\=2

\to p==2\times (1- \ righttail)\\\\\to \ righttail\ \ p = \text{NORM.S.DIST(2,TRUE)}

                        =0.977249868

\therefore \\P=2 \times (1-0.9772)\\\\P=0.0455\\\\P

Null hypothesis to dismiss  

Alternate solution assumptions embrace  

There is really no valid proof at the 5% stage that  

Knowledge is legacy

In choice d:

Possibly information such as this reflect a sample population with such a true p = 0.0455 meaning in the hypothesis  

u is around 100.  

11 +001

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