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Semmy [17]
3 years ago
7

Solve for x in the equation x2 + 4x-4-8-

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

A

Step-by-step explanation:

x2+4x-4-8

x2+4x-12

x2+6x-2x-12

x(x+6)-2(x+6)

(x-2)(x+6)

Either

x-2=0 OR x+6=0

x=2 OR x=-6

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If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
Solve the equation by completing the square. Round to the nearest hundredth if necessary? X^2+3x=24
Genrish500 [490]
X^2+3x=24, halve the linear coefficient, square it, and add it to both sides

In this case (3/2)^2=2.25

x^2+3x+2.25=26.25 now the left side is a perfect square...

(x+1.5)^2=26.25  take the square root of both sides

x+1.5=±√26.25  subtract 1.5 from both sides

x=-1.5±√26.25

x=-1.5-√26.25 and -1.5+√26.25

x≈ -6.62 and 3.62
6 0
3 years ago
What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s
Mrrafil [7]

Answer:

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of \stackrel{\large{\frown}}{ADC}

The\ sum\ of\ angles\ in\ a\ circle\ is 360^{\circ}.

So, we have:

\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB}  + \stackrel{\large{\frown}}{BPC}  = 360^{\circ}

Where:

\stackrel{\large{\frown}}{APB}  = 70^{\circ}

\stackrel{\large{\frown}}{BPC}  = 104^{\circ}

Substitute these values in the above equation.

\stackrel{\large{\frown}}{ADC} + 70^{\circ}   +104^{\circ}   = 360^{\circ}

\stackrel{\large{\frown}}{ADC} + 174^{\circ}   = 360^{\circ}

Collect Like Terms:

\stackrel{\large{\frown}}{ADC}    = 360^{\circ} - 174^{\circ}

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

7 0
3 years ago
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Which shapes appear to have perpendicular sides
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A square, rectangle, rhombus (I think)
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The left and right page numbers on an
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The pages would be 166 and 167
7 0
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