A kite is flying directly over a straight path 100m long.The angle of elevation of the kit from one end of the path is 35 °.from
the other end of the path the angle of elevation of the kite is 55°.how high is the kite?
1 answer:
Answer:
47 m
Step-by-step explanation:
In the attached diagram, we find angle AKB to be ...
180° -55° -35° = 90°
Then the length of AK is ...
AK = AB·cos(35°)
and the height of the kite is ...
height = AK·sin(35°) = AB·sin(35°)cos(35°) = (AB/2)sin(2·35°)
height = 50·sin(70°) = 46.98
The height of the kite is about 47 meters.
You might be interested in
Answer:
A ≈ 26.42
Step-by-step explanation:
<em><u>The shape presented is a circle, and the formula for this is:</u></em>
A = π
<em><u>The "</u></em><em><u>," is the radius (2.9), so plug this into the formula:</u></em>
A = π
A = π8.41
A ≈ 26.42
Answer:
1) (-42,0)
2) 2x-y=4
3) y-2x=-3
Step-by-step explanation:
y=mx+b
y=3/7x+18
-18=3/7x
x=-42
(It may be wrong because I am sort of rusty on this stuff)
