Question

A kite is flying directly over a straight path 100m long.The angle of elevation of the kit from one end of the path is 35 °.from the other end of the path the angle of elevation of the kite is 55°.how high is the kite?​

Answer 1

Answer:

  47 m

Step-by-step explanation:

In the attached diagram, we find angle AKB to be ...

  180° -55° -35° = 90°

Then the length of AK is ...

  AK = AB·cos(35°)

and the height of the kite is ...

  height = AK·sin(35°) = AB·sin(35°)cos(35°) = (AB/2)sin(2·35°)

  height = 50·sin(70°) = 46.98

The height of the kite is about 47 meters.