A kite is flying directly over a straight path 100m long.The angle of elevation of the kit from one end of the path is 35 °.from
the other end of the path the angle of elevation of the kite is 55°.how high is the kite?
1 answer:
Answer:
47 m
Step-by-step explanation:
In the attached diagram, we find angle AKB to be ...
180° -55° -35° = 90°
Then the length of AK is ...
AK = AB·cos(35°)
and the height of the kite is ...
height = AK·sin(35°) = AB·sin(35°)cos(35°) = (AB/2)sin(2·35°)
height = 50·sin(70°) = 46.98
The height of the kite is about 47 meters.
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