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Arlecino [84]
3 years ago
6

A kite is flying directly over a straight path 100m long.The angle of elevation of the kit from one end of the path is 35 °.from

the other end of the path the angle of elevation of the kite is 55°.how high is the kite?​

Mathematics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

  47 m

Step-by-step explanation:

In the attached diagram, we find angle AKB to be ...

  180° -55° -35° = 90°

Then the length of AK is ...

  AK = AB·cos(35°)

and the height of the kite is ...

  height = AK·sin(35°) = AB·sin(35°)cos(35°) = (AB/2)sin(2·35°)

  height = 50·sin(70°) = 46.98

The height of the kite is about 47 meters.

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