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Nitella [24]
3 years ago
9

Please help!!

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

-18 > 17

Step-by-step explanation:

-2(12.8) + 6 > 17 (don't have the equal greater than sign) Simplify

-24 + 6 > 17

-18 > 17

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What is the mother land<br><br> A-Mother russia<br><br> B-Morther amica<br><br> C-mother shrek
balu736 [363]

Answer:

A

Step-by-step explanation:

Mother Russia is the mother land

5 0
3 years ago
Somebody <br> help me!!!<br> god will bless you
irga5000 [103]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
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PLEASE HELP FOR 48 POINTS PLEASE!<br><br><br><br> show/explain your answer and work
pentagon [3]

Answer:

c  This is the direct variation

Step-by-step explanation:

The equation for direct variation is y= kx

Solving this for k

y/x =k

So y/x must be a constant

a.  9/3 =3

2/7 does not =3  so this is not a direct variation


b 1/2 = .5

-3/6 = -.5

This is not the same so this is not a direct variation


c.  27/9 =3

18/6 =3

9/3 =3

This is a direct variation with a constant of 3


d 5/-7 = -5/7

1/-3 = -1/3

This is not the same so this is not a direct variation

4 0
3 years ago
Read 2 more answers
Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0
4 years ago
Find the value of x,
Gekata [30.6K]

Answer: x = -7

Concept:

From the given graph, we can see that it is an isosceles triangle since the two base angles are congruent.

In geometry, an isosceles triangle is a triangle that has two sides of equal length.

If you are still confused, you may refer to the attachment below for a graphical explanation or tell me.

Solve:

<u>Given information</u>

First Side = 7

Second Side = x + 14

<u>Given expression deducted from the definition of an isosceles triangle</u>

Second Side = First Side

<u>Substitute values into the expression</u>

x + 14 = 7

<u>Subtract 14 on both sides</u>

x + 14 - 14 = 7 - 14

\boxed{x=-7}

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
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