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Andrews [41]
3 years ago
12

A right triangle's hypotenuse has length 5. If one leg has length 3, what is the length of the other leg?

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0
Answer:

a^2 + b^2 = c^2
3^2 + b^2 = 5^2
9 + b^2 = 25
b = _/16
b = 4

Explanation:

Pythagorean Theorem
n200080 [17]3 years ago
6 0

Answer:

The length of the other leg will be = 4

Step-by-step explanation:

You have to use your Pythagoras theorem to determine the length of the other leg.

Hypotenuse^2=a^2+b^2

since you are given the length of the hypotenuse and one leg you can change the formula to:

b^2 = h^2 - a^2

b = √h^2-a^2

b=√5^2-3^2

b=√25-9

b=√16

b=4

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

4 0
2 years ago
What is 8 × 1 + 3 × 0.1 + 9 × 0.01 in standard form
emmasim [6.3K]

Answer:

0.216

Step-by-step explanation:

8 \times 1 \times 3 \times 0.1 \times 9 \times 0.01\\\\=(8\times1)(3\times0.1)(9\times0.01)\\\\=8(0.3)(0.09)\\\\=(8\times0.3)(0.09)\\\\=(2.4)(0.09)\\\\=2.4\times0.09\\\\=0.216

is this the standard form?

5 0
3 years ago
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