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Andrews [41]
3 years ago
12

A right triangle's hypotenuse has length 5. If one leg has length 3, what is the length of the other leg?

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0
Answer:

a^2 + b^2 = c^2
3^2 + b^2 = 5^2
9 + b^2 = 25
b = _/16
b = 4

Explanation:

Pythagorean Theorem
n200080 [17]3 years ago
6 0

Answer:

The length of the other leg will be = 4

Step-by-step explanation:

You have to use your Pythagoras theorem to determine the length of the other leg.

Hypotenuse^2=a^2+b^2

since you are given the length of the hypotenuse and one leg you can change the formula to:

b^2 = h^2 - a^2

b = √h^2-a^2

b=√5^2-3^2

b=√25-9

b=√16

b=4

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3 years ago
A $33$-gon $P_1$ is drawn in the Cartesian plane. The sum of the $x$-coordinates of the $33$ vertices equals $99$. The midpoints
lisabon 2012 [21]

1.<span>
The midpoint </span>MPQ of PQ is given by  (a + c / 2, b + d / 2)<span>

2.
Let the x coordinates of the vertices of P_1 be : 

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the x coordinates of P_2 be :

</span>z1, x2, x3,…z33<span>

and the x coordinates of P_3 be:


w1, w2, w3,…w33</span>

<span>
3.
We are given with: 


</span>

X1 + x2 + x3… + x33 = 99

We also want to find the value of w1 + w2 + w3… + w33.<span>

4.

Now, based from the midpoint formula:</span>

 

Z1 = (x1 + x2) / 2

Z2 = (x2 + x3) / 2

Z3 = (x3 + x4) / 2

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and 

</span>

<span>W1 = (z1 + z1) / 2


W2 = (z2 + z3) / 2</span>

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W13 = (z33 + z1) / 2

.
.

5.</span>

<span>W1 + w1 + w3… + w33 = (z1 + z1) / 2 +  (z2 + z3) / 2 + (z33 + z1) / 2 = 2 (z1 + z2 + z3… + z33) / 2</span>

<span>Z1 + z1 + z3… + z33 = (x1 + x2) / 2 + (x2 + x3) / 2 + (x33 + x1) / 2

</span>2 (x1 + x2 + x3… + x33) / 2 = (x1 + x2 + x3… + x33 = 99<span>


<span>Answer: 99</span></span>

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3 years ago
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