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victus00 [196]
3 years ago
7

If angle bdc=23 and arc ef=34, determine arc abd using the appropriate theorems and postulates.

Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0

m(ar ABD) = 57°

Solution:

The given question have mistake. The correct question is wiiten below.

If angle BCD = 23° and arc EF = 34°, determine arc abd using the appropriate theorems and postulates.

Given data:

m∠BCD = 23° and m(ar EF) = 34°

By central angle theorem,

<em>The measure of a central angle is equal to the measure of the intercepted arc.</em>

m (ar EF) = m∠ECF

m∠ECF = 34°

By vertical angle theorem,

<em>If two lines are intersecting, then vertically opposite angles are equal.</em>

⇒ m∠ACB = m∠ECF

⇒ m∠ACB = 34°

m∠ACD = m∠ACB + m∠BCD

              = 34° + 23°

m∠ACD = 57°

By central angle theorem,

m(ar ABD) = m∠ACD

m(ar ABD) = 57°

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The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre
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Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

f(x)=b+mx

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

  • At 104 chirps per minute, the temperature is 63 ºF.
  • At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and  y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

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Solving for b

b=81-\frac{1}{4} (176)=37

Therefore, the linear function is

y=\frac{1}{4} \cdot x+37

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (124)+37=68

For 68 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (68)+37=54

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