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borishaifa [10]
4 years ago
7

COULD SOMONE PLZ PLZ HELP ME WITH THIS PROBLEM!!!

Mathematics
1 answer:
Jlenok [28]4 years ago
6 0
1.b 2.a lines are parallel hope this helps =3

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What’s is the corrects order?
LiRa [457]

unlikely

impossible

certain

likely

8 0
4 years ago
Please help I cannot figure this one out!
ra1l [238]

Answer:

77.47%

Step-by-step explanation:

We have to use Bayes Theorem in solving this problem.

This theorem's formula is:

P(A | B) = \frac{P(A and B)}{P(B)}

Where the " | " means <u><em>"given that"</em></u>.

For our problem, using bayes theorem, we can write:

P(Student has lice | positive ) = \frac{P(StudentHasLice and Positive)}{P(Positive)}

  • P(Positive) = 0.1692 + 0.0492 = 0.2184
  • P (Student has Lice & Positive ) = 0.1692

So P(Student has lice | Positive ) = \frac{0.1692}{0.2184}=0.7747

4 0
3 years ago
Simplify the expression <br> 9y+4-6y
Mashutka [201]

Answer:

3y+4

Step-by-step explanation:

9y-6y=3y

3 0
3 years ago
Please help me!! It's some sort of PreAP math stuff
olga55 [171]

Answer:

12x + 40y

Step-by-step explanation:

4(3x+10y)

multiply the outer number (4) with all the terms inside the parentheses

4 X 3x + 4 X 10y

12x + 40y

3 0
3 years ago
A container manufacturing company was contracted to design and manufacture cylindrical cans for fruit juice. The volume of each
gtnhenbr [62]

The volume of the cylinder is the amount of fruit juice it can contain.

The relationship between the volume and the surface area is:

\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}

The given parameter is:

\mathbf{V = 0.946}

The volume of a cylinder is calculated as:

\mathbf{V = \pi r^2 h}

Make h the subject

\mathbf{h = \frac{V}{ \pi r^2}}

The surface area (A) of a cylinder is:

\mathbf{A = \pi r^2 + \pi rh}

Substitute \mathbf{h = \frac{V}{ \pi r^2}}

\mathbf{A = \pi r^2 + \pi r \times \frac{V}{\pi r^2}}

\mathbf{A = \pi r^2 + \frac{V}{r}}

Differentiate

\mathbf{A' = 2\pi r - Vr^{-2}}

Set to 0

\mathbf{2\pi r - Vr^{-2} = 0}

Rewrite as:

\mathbf{ 2\pi r = Vr^{-2}}

Multiply through by r^2

\mathbf{ 2\pi r^3 = V}

Solve for r

\mathbf{r = \sqrt[3]{\frac{V}{2\pi}}}

\mathbf{A = \pi r^2 + \frac{0.946}{r}}

So, we have:

\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}

Hence, the relationship between the volume and the surface area is:

\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}

Read more about surface areas and volumes at:

brainly.com/question/3628550

8 0
2 years ago
Read 2 more answers
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