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4 years ago

COULD SOMONE PLZ PLZ HELP ME WITH THIS PROBLEM!!!

Mathematics

1 answer:

Jlenok [28]4 years ago

6 0

1.b 2.a lines are parallel hope this helps =3

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What’s is the corrects order?

LiRa [457]

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likely

8 0

4 years ago

Please help I cannot figure this one out!

ra1l [238]

Answer:

77.47%

Step-by-step explanation:

We have to use Bayes Theorem in solving this problem.

This theorem's formula is:

P(A | B) = $\frac{P(A and B)}{P(B)}$

Where the " | " means "given that".

For our problem, using bayes theorem, we can write:

P(Student has lice | positive ) = $\frac{P(StudentHasLice and Positive)}{P(Positive)}$

P(Positive) = 0.1692 + 0.0492 = 0.2184
P (Student has Lice & Positive ) = 0.1692

So P(Student has lice | Positive ) = $\frac{0.1692}{0.2184}=0.7747$

4 0

3 years ago

Simplify the expression 9y+4-6y

Mashutka [201]

Answer:

3y+4

Step-by-step explanation:

9y-6y=3y

3 0

3 years ago

Please help me!! It's some sort of PreAP math stuff

olga55 [171]

Answer:

12x + 40y

Step-by-step explanation:

4(3x+10y)

multiply the outer number (4) with all the terms inside the parentheses

4 X 3x + 4 X 10y

12x + 40y

3 0

3 years ago

A container manufacturing company was contracted to design and manufacture cylindrical cans for fruit juice. The volume of each

gtnhenbr [62]

The volume of the cylinder is the amount of fruit juice it can contain.

The relationship between the volume and the surface area is:

$\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}$

The given parameter is:

$\mathbf{V = 0.946}$

The volume of a cylinder is calculated as:

$\mathbf{V = \pi r^2 h}$

Make h the subject

$\mathbf{h = \frac{V}{ \pi r^2}}$

The surface area (A) of a cylinder is:

$\mathbf{A = \pi r^2 + \pi rh}$

Substitute $\mathbf{h = \frac{V}{ \pi r^2}}$

$\mathbf{A = \pi r^2 + \pi r \times \frac{V}{\pi r^2}}$

$\mathbf{A = \pi r^2 + \frac{V}{r}}$

Differentiate

$\mathbf{A' = 2\pi r - Vr^{-2}}$

Set to 0

$\mathbf{2\pi r - Vr^{-2} = 0}$

Rewrite as:

$\mathbf{ 2\pi r = Vr^{-2}}$

Multiply through by r^2

$\mathbf{ 2\pi r^3 = V}$

Solve for r

$\mathbf{r = \sqrt[3]{\frac{V}{2\pi}}}$

$\mathbf{A = \pi r^2 + \frac{0.946}{r}}$

So, we have:

$\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}$

Hence, the relationship between the volume and the surface area is:

$\mathbf{A = \pi (\sqrt[3]{\frac{V}{2\pi}})^2 + \frac{0.946}{(\sqrt[3]{\frac{V}{2\pi}})}}$

Read more about surface areas and volumes at:

brainly.com/question/3628550

8 0

2 years ago

Read 2 more answers