3 years ago

The sum of two consecutive odd integers is 236 what is the smaller integer

1 answer:

3 0

The correct answer is 117

x + y = 236
y = x + 2
x + x + 2 = 236
2x = 236 - 2
2x = 234
x = 234/2
x = 117

y = 117 + 2
y =119

Both are odd integers and 117 is smaller.

You might be interested in

A rectangle has dimensions 3x-1 and x+6. Write an expression for the area of the rectangle as a polynomial in standard form

WITCHER [35]

Answer:

the area product is simply (3x+5).(x+7 which can multiply if desired to obtain highlight3x/2+ 26x + 35.

You can use Completion of the Square on the trinomial product to put this trinomial into standard form. You would want this form to be like (x-h)2 +k.

7 0

3 years ago

What is -4R-2r+5 as a simpler exspression

enyata [817]

$\sf-4R-2r+5$ is already in simplest form.

But if you meant to say $\sf-4r-2r+5$ , we would combine the first two terms.

Adding/subtracting like terms is the same as adding/subtracting whole numbers.

$\sf-4-2=-6$

Therefore:

$\sf-4r-2r=-6r$

Which gives us:

$\boxed{\sf-6r+5}$