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Neko [114]
3 years ago
10

M-2<-8 or m/8>1I don't know how to solve this

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0
I hope this helps you

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A 5.0g of salt was weighed by Victoria as 5.1g. What is the percentage error?​
Aleksandr-060686 [28]

qwerty blablablablabal

7 0
3 years ago
The square below has an area of 1+2x+x2 square meters. What expression represents the length of one side of the square?
vovikov84 [41]

Answer:

x+1

Step-by-step explanation:

A square = side* side

x²+2x+1 = (x+1)(x+1)

side = (x+1)

3 0
3 years ago
Plz help my teacher isn’t emailing my back
nalin [4]

Answer:

ugh'

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The ratio of ages of kissi and esinam is 3:5 and esinam is 3:5 The sum of ages of all 3 is 147 years.whats the age difference be
Sergio039 [100]

Answer:

48 years.

Step-by-step explanation:

Consider the complete question is "The ratio of ages of kissi and esinam is 3:5 and that of esinam and lariba is 3:5. The sum of ages of all 3 is 147 years. whats the age difference between oldest and youngest ?"

It is given that

Kissi : Esinam = 3:5 = 9:15

Esinam : Lariba = 3:5 = 15:25

So, the combined ratio is Kissi : Esinam : Lariba = 9:15:25

Let ages of Kissi, Esinam, Lariba are 9x, 15x and 25x.

Sum of ages of all 3 is 147 years.

9x+15x+25x=147

49x=147

x=3

The value of x is 3. So, the age of all three are

Kissi=9x=9(3)=27

Esinam=15x=15(3)=45

Lariba=25x=25(3)=75

Since Lariba is oldest and Kissi is youngest, therefore, the difference between their ages is

75-27=48

Hence, difference between oldest and youngest is 48 years.

8 0
3 years ago
A researcher wants to test to see if husbands are significantly older than their wives. To do this, he collects the ages of husb
OLga [1]

Complete Question

The complete is shown on the first uploaded image

Answer:

The correct option are option 2 and option 4

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 12  

    The test statistics is  t \approx 1.434

    The level of significance is  \alpha = 0.05

    The  rejection region is    t>1.796

   The null hypothesis H_o: \mu_d=0

    The alternative hypothesis is  H_a : \mu_d >0

 From the given values we see that t <  1.796(i.e   1.434 < 1.796 ) which implies that t is not within the rejection region

  Hence we fail to reject the null hypothesis

The conclusion is that there is insufficient evidence to suggest that that the husbands are significantly older than the wife.

4 0
3 years ago
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