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andreev551 [17]
3 years ago
5

Write a recursive rule for the sequence. Assume it starts with the 1st term. 10, 14, 18, 21...

Mathematics
1 answer:
Papessa [141]3 years ago
3 0

Option D is correct. The correct option for the recursive formula is f(0) =6;f(n)=f(n - 1)+4

Given the sequence 10, 14, 18...

The first term is 10, hence

a1 = 10

The previous terms will be a_{n-1}

From the sequence, we can see that <em>4 is being added to the previous term to get the next term</em>. Hence the nth term will be expressed as:

a_n = a_{n-1} + 4

Get the term before the first term a_0

If n = 1

a_1 = a_{1-1} + 4\\a_1 = a_{0} + 4\\a_0=a_1-4\\a_0=10-4\\a_0=6

Hence the correct option for the recursive formula is f(0) =6;f(n)=f(n - 1)+4

Learn more here: brainly.com/question/18233843

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which geometric series represents 0.4444... as a fraction? a) 1/4, 1/40, 1/400, 1/4,000 b) 1/40, 1/400, 1/4,000, 1/40,000 c) 4/1
xenn [34]

Answer: \frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}


Step-by-step explanation:

The given geometric series are:

a)\frac{1}{4}+\frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}

on simplifying in decimals, we get

0.25+0.025+0.0025+0.00025=0.27775\neq0.4444

b) \frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}+\frac{1}{40,000}

on simplifying in decimals, we get

0.025+0.0025+0.00025+0.000025=0.027775\neq0.4444

c)\frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}

on simplifying in decimals, we get

0.4+0.04+0.004+0.0004=0.4444

Thus, this geometric series represent 0.4444.

d)\frac{1}{10}+\frac{1}{100}+\frac{1}{1,000}+\frac{1}{10,000}

on simplifying in decimals, we get

0.1+0.01+0.001+0.0001=0.1111\ \neq0.4444

7 0
4 years ago
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