Question

There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller number. Find the two numbers. Answer: If the smaller number is x, the equation will be . The numbers in ascending order are:
BRAINLIEST IF CORRECT

Answer 1

Answer:

Smaller number: 12

Greater number: 31

Step-by-step explanation:

Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

1) Translate the information into equations

"One is 7 more than twice the other"

⇒ $y=2x+7$

"The sum of the numbers is 43"

⇒ $x+y=43$

2) Use substitution to solve for the smaller number

$x+y=43$

Plug the equation $y=2x+7$ into the above equation

$x+(2x+7)=43\\x+2x+7=43\\3x+7=43$

Subtract both sides by 7

$3x+7-7=43-7\\3x=36$

Divide both sides by 3 to isolate x

$\frac{3x}{3} = \frac{36}{3} \\x=12$

Therefore, the smaller number equates to 12.

3) Use substitution to solve for the greater number

$x+y=43$

Plug in x as 12

$12+y=43$

Subtract both sides by 12 to isolate y

$12+y-12=43-12\\y=31$

Therefore, the greater number equates to 31.

I hope this helps!