1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pepsi [2]
3 years ago
12

How do you innovate or improve a product?

Computers and Technology
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:in order to innovate or improve a product you need to have an idea

Explanation:

You might be interested in
Two functions of the UPS​
Angelina_Jolie [31]

Answer:

UPS is abbreviation of Uninterrupted power supply. It is a battery backup devices useful when major supply is interrupted due to any reason.

It performs the following functions:

1. It provides protection from power surges.

2. Smooth out noisy power sources

5 0
3 years ago
Read 2 more answers
Choose the term that best matches the definition.
Y_Kistochka [10]

Answer: it’s network protocol

Explanation:

4 0
3 years ago
class llist { private: record * start; char filename[16]; int readfile(); int writefile(); record * reverse(record * ); void cle
Sophie [7]

Answer:

See Explaination

Explanation:

#include <cstdlib>

#include <iostream>

#include <iomanip>

#include <fstream>

#include <string>

#include <sstream>

using namespace std;

struct Person

{

string name;

string addr;

string phone;

string id;

};

const int MAX_SIZE = 8;

void addData(Person list[], int& size);

void dispData(const Person list[], int size);

void delData (const Person list[], int size);

void saveFile(const Person list[], int size);

void openFile(Person list[], int& size);

char getMenuResponse();

int main(int argc, char *argv[])

{

Person contactList[MAX_SIZE];

int numOfRecs = 0;

bool run = true;

do

{

cout << "Address Book - " << numOfRecs << " Number of Contacts" << endl;

switch ( getMenuResponse() )

{

case 'A': addData(contactList, numOfRecs); break;

case 'D': dispData(contactList, numOfRecs); break;

case 'T': delData(contactList, numOfRecs); break;

case 'O': openFile(contactList, numOfRecs); break;

case 'S': saveFile(contactList, numOfRecs); break;

case 'Q': run = false; break;

default : cout << "That is NOT a valid choice" << endl;

}

} while (run);

cout << endl << "Program Terminated" << endl;

return EXIT_SUCCESS;

}

void addData(Person list[], int& size)

{

Person tmp;

char response;

char str[256];

if (size < MAX_SIZE) {

system("cls");

cout << "Enter Contact Information" << endl << endl;

cout << "Name: ";

cin.getline(str, 256, '\n');

tmp.name = str;

cout << endl;

cout << "Address: ";

cin.getline(str, 256, '\n');

tmp.addr = str;

cout << endl;

cout << "Phone Number: ";

cin.getline(str, 256, '\n');

tmp.phone = str;

cout << endl;

cout << "E-mail id Address: ";

cin.getline(str, 256, '\n');

tmp.id = str;

cout << endl;

cout << "Add Contact to Address Book? (y/n) ";

cin >> response;

if (toupper(response) == 'Y')

list[size++] = tmp;

} else {

cout << "Sorry, Address Book is currently full." << endl;

system("pause");

}

system("cls");

}

void dispData(const Person list[], int size)

{

system("cls");

if(size < 1)

{

cout << "Nothing to display" << endl;

} else {

cout << "Contacts :" << endl << endl;

cout << fixed << setprecision(2);

cout << "Contact Name Address Phone No. ID" << endl;

cout << left;

for (int i = 0; i < size; i++)

{

cout << setw(10) << list[i].name << right

<< setw(10) << list[i].addr<<right

<< setw(10) << list[i].phone<<left

<< setw(15) << list[i].id<<left<<endl;

}

cout << right << setw(3) << size;

cout << " Contacts"<< endl;

}

system("PAUSE");

system("cls");

}

void delData(const Person list[],int size) {

vector<Person> :: iterator vItr = Contact.begin();

while (vItr != Contact.end() )

{

if (vItr->Name == Name)

{

vItr = Contact.erase (vItr);

break;

}

else

vItr++;

}

void saveFile(const Person list[], int size) {

string fileName;

ofstream outfi;

cout<<"Enter file name: ";

getline(cin,fileName);

outfi.open(fileName.c_str());

if (!outfi.fail()) {

system("cls");

cout << "Saving Address Book to the disc ";

for(int i = 0; i < size; i++) {

outfi << list[i].name << ';'

<< list[i].addr<< ';';

if (i < size-1) outfi << endl;

}

cout << endl << size << " Address Book in the disc." << endl;

outfi.close();

system("PAUSE");

system("cls");

}

else {

cout << "ERROR: problem with file" << endl;

system("PAUSE");

system("cls");

}

}

void openFile(Person list[], int& size)

{

ifstream infi("AddressBook.txt");

string str;

stringstream strstrm;

if (!infi.fail()) {

system("cls");

cout << "Reading Address Book from the disc ";

size = 0;

while(!infi.eof() && size < MAX_SIZE)

{

getline(infi, str, ';');

list[size].name = str;

getline(infi, str, ';');

strstrm.str(""); strstrm.clear();

strstrm << str;

strstrm >> list[size].addr;

}

cout << endl << size << " read contacts from the disc." << endl;

system("PAUSE");

system("cls");

}

else {

cout << "ERROR :file not accepted" << endl;

system("PAUSE");

system("cls");

}

}

char getMenuResponse()

{

char response;

cout << endl << "take chioce" << endl

<< "(A)dd contact, (D)isplay contact0, (O)pen File, (S)ave File, (Q)uit" << endl

<< "> ";

cin >> response;

cin.ignore(256, '\n');

return toupper(response);

}

8 0
3 years ago
How does tracking changes relate to sharing a workbook in Excel?
ElenaW [278]

Answer:When you highlight changes as you work, Excel outlines any revisions (such as changes, insertions, and deletions) with a highlighting color. On the Review tab, click Track Changes, and then click Highlight Changes. Select the Track changes while editing. This also shares your workbook check box.

Explanation:

8 0
2 years ago
To iterate through (access all the entries of) a two-dimensional arrays you
ahrayia [7]

Answer: You would need two loops to iterate through both dimensions

Explanation:

matrix = [[1,2,3,4,5],

              [6,7,8,9,10],

              [11,12,13,14,15]]

for rows in matrix:

    for numbers in rows:

         print(numbers)

The first loop cycles through all the immediate subjects in it, which are the three lists. The second loop calls the for loop variable and iterates through each individual subject because they are lists. So the first loop iterates through the 1st dimension (the lists) and the seconds loop iterates through the 2nd dimension (the numbers in the lists).

6 0
3 years ago
Other questions:
  • Match the software requirements of a server to their purpose
    5·1 answer
  • There are several methods of updating information and data on a webserver. We must consider who performs those updates upfront w
    9·2 answers
  • Mobile apps known as news _________ collect articles from a variety of sources and present them to you in a magazine-style forma
    7·2 answers
  • Write a statement that adds 1 to the variable reverseDrivers if the variable speed is less than 0,adds 1 to the variable parkedD
    14·1 answer
  • What layer in the Transmission Control Protocol/Internet Protocol (TCP/IP) model is responsible for defining a way to interpret
    11·1 answer
  • __________ intelligence is an approach to boundary spanning which results from using sophisticated software to search through in
    15·1 answer
  • An ____ is an object that produces each element of a container, such as a linked list, one element at a time.
    13·2 answers
  • 3.5 Code Practice: Question 1<br> (Website: Edhesive)
    14·1 answer
  • Rita tried unsuccessfully to open a PDF file attachment in her Inbox by double-clicking the attachment in the Reading Pane. What
    8·1 answer
  • Which of the following is a key aspect of any IT position? installation of fiber optic cables
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!