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seraphim [82]
2 years ago
5

Which prism has a greater volume? Prism.

Mathematics
1 answer:
Likurg_2 [28]2 years ago
6 0

Answer:

the first prism looks like a cuboid .

therefore , volume of prism 1 = l × b × h

\bold{7  \times 2 \times 1} \\\bold{   =  > 14 \: units {}^{3}}

and ,

the second prism looks like a cuboid too

thus , volume of prism 2 = l × b × h

\bold{3 \times 3 \times 2} \\\bold{  =  > 18 \:  units {}^{3}}

thus , prism 2 has a greater volume.

hope helpful ~

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Please help.<br> Algebra.
Akimi4 [234]

1. A

Since parallel lines never cross, then there can be no intersection; that is, for a system of equations that graphs as parallel lines, there can be no solution. This is called an "inconsistent" system of equations, and it has no solution.

--------------------------------------------------------------------------------------------------------------

2. C

That's right. If a system of equations has a solution, then their graphs intersect,  and the point where they intersect is the solution because it's the point that  satisfies each equation in the system.

Straight-line graphs with the same slope are parallel lines, and they never intersect,  which is another way of saying they have no solution.

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3 years ago
7. x – 5y = 4<br>2x + 14 = y​
const2013 [10]
This is your answer.... all you are doing is substituting what ever the variable is

4 0
3 years ago
The perimeter of a rectangular field is 200 feet. The length of the field is 7 feet more than two times the width of the field.
bulgar [2K]
X = 2y + 7 ...............(1)
2x + 2y = 200 ........(2)

Substituting the expression for x in equation (1) into equation (2) gives
2(2y + 7) + 2y = 200 .....(3)
Equation (3) simplifies to
6y = 186
Therefore y = 31 feet.
Substituting the value for y into (1) gives
x = 69 feet.
8 0
3 years ago
Solve using the box method
Lena [83]

\huge\text{Hey there!}

\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}

\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}

\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}

\large\text{Equation: }\mathsf{\dfrac{(2x)^2-3^2}{2x + 3}}

\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}

\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}

\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}

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\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}

3 0
3 years ago
Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What
sveticcg [70]

Answer:

Area of rectangle = 196\,m^2

Length of rectangle = 14 m

Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function y=f(x) has a point of maxima at x=x_0 if f''(x_0)

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

=2(x+y)

Also, perimeter of rectangle is equal to 56 m.

So,

56=2(x+y)\\x+y=28\\y=28-x

Let A denotes area of rectangle.

A = length × width

A=xy\\=x(28-x)\\=28x-x^2

Differentiate with respect to x

\frac{dA}{dx}=28-2x

Put \frac{dA}{dx}=0

28-2x=0\\2x=28\\x=14

Also,

\frac{d^2A}{dx^2}=-2

At x = 14, \frac{d^2A}{dx^2}=-2

So, x = 14 is a point of maxima

So,

y=28-x=28-14=14

Area of rectangle:

A=xy=14(14)=196\,m^2

Length of rectangle = 14 m

Width of rectangle = 14 m

5 0
3 years ago
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