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notka56 [123]
3 years ago
10

The table shows the number of candies packed by Machine J. The equation shows the number of candies packed by Machine K. In both

representations, x is a measure of the number of minutes and y is a measure of the number of candies packed.
Machine J Candy Packing

x (minutes) y (candies)
3 90
6 180
9 270
12 360

Machine K: y = 26x

How many more candies could machine J pack than machine K in 11 minutes?
30
44
90
330
Mathematics
1 answer:
pav-90 [236]3 years ago
3 0
Machine K y= 26x
y = 26 (11)
y = 286 candies in 11 minutes from Machine K

Machine J
90 / 3 = 30 candies a minute * 11 minutes = 330 candies

330 - 286 = 44

Machine J can pack 44 more candies than Machine K in 11 minutes.
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\text {5*6=30}

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\text {Your Answer Would Be:}

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\text {A: It means to divide. So if someone says simplify 2/4 that means divide.}

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The cost c, to produce b baseball bats per day is modeled by the function c(b)=0.06b^2 - 7.2b + 390. What number of bats should
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One possibility: 
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The other choice:
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If you produce any other number of bats in a day ... more than zero
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