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AlekseyPX
3 years ago
9

To solve the logarithmic inequality below, Braden

Mathematics
2 answers:
liraira [26]3 years ago
6 0

Answer: B and E

Step-by-step explanation:

anygoal [31]3 years ago
3 0

Answer:

b and e

b is The solution set is the interval (5, 14).

e is The ordered pair (32, 3) could be included in the table.

Step-by-step explanation:

got it right on edge

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Step-by-step explanation:

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I'm given that log4=0.602 and log12=1.079
Rudiy27

log(3) = log(12/4)

Use the quotient rule [ \text{log}_a\frac{x}{y}=log_ax-log_ay ] to simplify.

log(12/4) = log(12) - log(4)

Simplify using the given values for 12 and 4.

1.079 - 0.602

0.477

Therefore, log(12) ≈ 0.477

Best of Luck!

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(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

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=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

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Which statement regarding the number of solutions for the linear equation shown below is true?
stiks02 [169]

Answer: There is no solution.

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