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3 years ago

To solve the logarithmic inequality below, Braden

Mathematics

2 answers:

liraira [26]3 years ago

6 0

Answer: B and E

Step-by-step explanation:

anygoal [31]3 years ago

3 0

Answer:

b and e

b is The solution set is the interval (5, 14).

e is The ordered pair (32, 3) could be included in the table.

Step-by-step explanation:

got it right on edge

You might be interested in

3/8 + 1/4 + 1/2 - 2/3 =

Nostrana [21]

Answer:

$\frac{11}{24}$

Step-by-step explanation:

3/8 + 1/4 + 1/2 - 2/3

- > 1/4 = 2/8

3/8 + 2/8 + 1/2 - 2/3

5/8 + 1/2 - 2/3

- > 1/2 = 4/8

5/8 + 4/8 - 2/3

9/8 - 2/3

- > LCM of 8,3: 24

- > 9/8 = 27/24

- > 2/3 = 16/24

27/24 - 16/24

11/24

Hope this helps you.

7 0

3 years ago

If (126)n=86in base 10find the positive value of n

Evgen [1.6K]

Answer:

n= 0.682539 but if you want it in fraction form its 43/63

Step-by-step explanation:

6 0

3 years ago

HELP WITH 4 QUESTIONS!!!!

m_a_m_a [10]

When dilation is about the origin, as it is here in every case, the image point coordinates are the original (pre-image) coordinates multiplied by the scale factor.

1. Multiply every coordinate value by 5:

... W' = (-5, 10), X' = (-15, -5), Y' = (25, -5), Z' = (15, 10)

2. Multiply every coordinate value by 1/3:

... A' = (-2, 5), B' = (0, 5/3), C' = (1, 10/3)

3. A' = (2, 8), B' = (6, 2), C' = (2, 2)

4. The image coordinates are 5 times the original coordinates, so ...

... the scale factor of the dilation is 5.

5 0

3 years ago

How many cubes were used to make this figure?

Paha777 [63]

Answer:

I think its 30 I'm not 100% sure tho

3 0

3 years ago

Read 2 more answers

Earth revolves around the Sun in 365 days, but the planet Mercury does so in only 88 days. Compared to Earth, how many more comp

Elena L [17]

Answer:

In a 1000 days Mercury will make 8.624 more revolutions than Earth!

Step-by-step explanation:

<u>Earth</u> takes 365 days to make a complete revolution.

we can say that the rotational speed of Earth is $\dfrac{1}{365}\frac{\text{rev}}{\text{day}}$

so, in a 1000 days how many revolutions will Earth have made?

$\dfrac{1}{365}\frac{\text{rev}}{\text{day}}\times(1000\,\text{day})$

see that the 'day's cancel out. Simply multiply the two numbers!

$2.739\text{rev}$

<u>Next, do the same for Mercury</u>

we can say that the rotational speed of Mercury is $\dfrac{1}{88}\frac{\text{rev}}{\text{day}}$

as it completes 1 revolution in 88 days.

so, in a 1000 days how many revolutions will Mercury have made?

$\dfrac{1}{88}\frac{\text{rev}}{\text{day}}\times(1000\,\text{day})$

multiplying by 1/88 by 1000 yields:

$11.363\text{rev}$

The Question is how many MORE complete revolutions will Mercury make in 1000 days?

We need to subtract the revolutions of Mercury with Earth to find how far ahead is Mercury from Earth

$11.363\text{rev} - 2.739\text{rev}$

$8.624\text{rev}$

In a 1000 days Mercury will make 8.624 more revolutions than Earth!

5 0

3 years ago