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timurjin [86]
4 years ago
5

Triangle A″B″C″ is formed by a reflection over x = −3 and dilation by a scale factor of 3 from the origin. Which equation shows

the correct relationship between ΔABC and ΔA″B″C′

Mathematics
2 answers:
vovangra [49]4 years ago
6 0

Answer:

B

Step-by-step explanation:

took the test

Allisa [31]4 years ago
5 0

Answer:

  see below

Step-by-step explanation:

Each segment in ΔA"B"C" is 3 times the length of the corresponding segment in ΔABC. This is due to the dilation by a scale factor of 3.

Then you have ...

  \overline{A''B''}=3\overline{AB}\quad\text{or}\\\\\dfrac{\overline{AB}}{\overline{A''B''}}=\dfrac{1}{3}

The latter relation matches the second choice.

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. All the students in SS3 of a named school take either Mathematics (M), or Physics (P) or Chemistry (C). 40 take Mathematics, 4
aivan3 [116]

Answer:

(a) = 13

(b) = 8

(c) = 5

Step-by-step explanation:

Addition theorems on sets are

Theorem 1 :

n(AuB) = n(A) + n(B) - n(AnB)

Theorem 2 :

n(AuBuC) : = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

Total number of students in the school is not given

so let there are 60 students in the school

using theorem 2

n(AuBuC) : = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

let n(A) = Mathematics, n(B) =Physics and n(C) = Chemistry

so putting values,

   60             =    40 + 42 + 38 - 20 - 28 - 25 + n(AnBnC)

60 +73 -120 = n(AnBnC)

         13         = n(AnBnC)

therefore, there are total 13 students who take all three subjects

Number of students who had taken only Mathematics  =
n(A) - n(AnB) - n(AnC) + n(AnBnC)

40 - 20 - 25 + 13

53 - 45 = 8 students

Number of students who had taken only Physics  =

n(B) - n(BnA) - n(BnC) + n(AnBnC)

42 - 20 - 28 + 13

53 - 48 = 5 students

learn more about sets and vein diagrams at

brainly.com/question/2332158

#SPJ10

4 0
2 years ago
3<br> -<br> c –<br> - 5<br> 2<br> 1<br> g<br> I/<br> 1<br> -c – 1<br> 2
liq [111]
What does this mean? it’s all scrambled
7 0
3 years ago
How do you solve this?
liberstina [14]

Answer:

The answer is

<h2>{13}^{3}</h2>

Step-by-step explanation:

<h3>( {13})^{2}(  {13})^{ - 4} ( {13})^{5}</h3>

To solve the expression , use the rules of indices

Since the bases are the same and are multiplying we add the exponents

That's

<h3>{a}^{x}  \times  {a}^{y}  \times  {a}^{z}  =  {a}^{x + y + z}</h3>

So we have

<h3>( {13})^{2}(  {13})^{ - 4} ( {13})^{5}   =  {13}^{2 - 4 + 5}  \\  =  {13}^{ - 2 + 5}</h3>

We have the final answer as

<h3>{13}^{3}</h3>

Hope this helps you

3 0
4 years ago
If a translation maps ∠D onto ∠B, which of the following statements is true? triangle CAB, point E is on segment AC between poin
mrs_skeptik [129]

Answer:

The correct option is;

ΔCED ~ ΔCAB

Step-by-step explanation:

Given that the translation maps angle ∠D to angle ∠B, we have;

Angle ∠D is congruent to ∠B (Given)

Segment ED is parallel to segment AB (lines having similar angles to a common transversal)

Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)

∠C is congruent to ∠C reflexive property

Therefore, we have;

∠C ≅ ∠C

∠E ≅ ∠A  

∠D ≅ ∠B

Which gives ΔCED is similar to ΔCAB (not ΔCBA)

4 0
3 years ago
Which inequality is true? Use the number line to help.
KIM [24]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
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