happy paws $17.00 plus $3.50 per hour to keep a dog during the day. Woof charges $11.00 plus $4.75 per hour. complete equeation
1 answer:
You might be interested in
Answer:
See the proof below.
Step-by-step explanation:
For this case we need to proof that: Let be independent random variables with a common CDF
. Let
be their ECDF and let F any CDF. If
then
Proof
Let different values in the set {
} and we can assume that
represent the number of
that are equal to
.
We can define and assuming the probability
.
For the case when for any
then we have that the
And for the case when all and for at least one
we know that
for all the possible values
. So then we can define the following ratio like this:
So then we have that:
And the log for a number is 0 or negative when the number is between 0 and 1, so then on this case we can ensure that
And with that we complete the proof.
Answer:
c
Step-by-step explanation:
Here's how this works:
Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:
In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:
Put everything over the common denominator now:
Since , we will make that substitution:
We could separate that fraction into 2:
×
and
Therefore, the simplification is
sec(x)csc(x)