Answer:45 * t = 2.5 * (1-t)...the equation will have one solution.
Step-by-step explanation:
For this case, the first thing you should know is:
d: v * t
Where,
d: distance
v: speed
t: time
To go to school by bus we have:
d = 45 * t
To return from school we have:
d = 2.5 * (1-t)
how the distance is the same:45 * t = 2.5 * (1-t)
Answer: C)46 ft
Step-by-step explanation:
We know that the circumference of a circle can be calculated with this formula:

Where "r" is the radius of the circle.
Since John is putting a fence around his garden that is shaped like a half circle and a rectangle, then we can find how much fencing he needs by making this addition:

Where "l" is the lenght of the rectangle and "w" is the width of the rectangle.
Since we know that the radius of the circle is half its diameter, we can find "r". This is:

Then, substituting values (and using
), we get:

Answer:
A
Step-by-step explanation:
All of the values are represented correctly on the histogram. It represents both the points and the frequencies in the correct way.
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.