In both the figures we have a Right Angled Triangle.
Two sides of the right angled triangles are given and we are to find the Third side. This can be done using the Pythagoras Theorem, which states:
Hypotenuse² = Base² + Perpendicular²
For 1st figure, we have
Base = 21
Perpendicular = 20
So,
Hypotenuse² = 20² + 21² = 841
⇒
Hypotenuse = 29 (1st option is correct)
For 2nd Image, we have
Base= 6
Hypotenuse = 10
So, we can write:
10² = 6² + Perpendicular²
Perpendicular² = 64
⇒
Perpendicular = 8 (Option Fourth)
Answer:
a = -3/2 = -1.5
Step-by-step explanation:
(1+ax) (2+3x)³
Formula
(a+b)^3=a^3+3a^2b+3ab^2+b^3
(1 + ax) [ 2^3 + 3*2^2*3x + 3*2*(3x)^2 + (3x)^3]
(1 + ax) [ 8 + 12*3x + 6*9x^2 + 27x^3]
8 + 12*3x + <u>6*9x^2</u> + 27x^3 + 8ax + <u>36ax^2</u> + 54ax^3 + 27ax^4
coefficient of x^2 is zero
54x^2 + 36ax^2
54 + 36a = 0
36a = -54
a = -3/2
Answer:
Step-by-step explanation:

Answer:
x=13, 16(x-1)
Step-by-step explanation:
For 38, you have to first divide both sides by 2.
This becomes, x-6=7
Add 6 to both sides
x=13.
For 40. You can can distribute the 8.
This makes it 16x-16.
With this you can than, factor out the 16.
16(x-1).