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iren2701 [21]
3 years ago
10

Is number 11 help plz

Mathematics
1 answer:
LenKa [72]3 years ago
3 0
A) 1 gallon/5 pints
b) 3 quarts/5 pints
c) 5 pints/8 ounces
d)3 quarts/1 gallon
e) 8 ounce/1 gallon
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Anybody know the answers??? Helpppp
goldenfox [79]

Answer:

2. x = 135

Step-by-step explanation:

im not sure about question 1

8 0
3 years ago
The first 5 terms of a sequence are shown below:
nirvana33 [79]

Step-by-step explanation:

To find the formula for the nth term ,

First , find the common difference or common ratio.

Common difference =

T_2-T_1 \\  - 2 - 3 \\  =  - 5

Common ratio =

T_2/T_1 \\  \frac{ - 2}{3}

The common difference applies to the other given numbers for example :

T_3- T_2  =  - 7 - ( - 2) \\  =  - 7 + 2 =  - 5

this proves that it is an arithmetic sequence and the given formula for the nth term of an arithmetic sequence is

T_n =a(n-1)d

Where n = no of terms

a= first term

d= common difference

6 0
3 years ago
Which is it? please help me and i will give brainliest
Cerrena [4.2K]

Answer: A, 1/2

Step-by-step explanation:

he is simply using 1 cup of bs for each cup of ws so when you do it its i cup of ws then its hald of 1 bs

3 0
3 years ago
Read 2 more answers
Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0
fomenos

• The value of the discriminant ,D= -16

,

• The solution to the quadratic equation is

x=\frac{1+2i}{5}\text{     or    }\frac{1-2i}{5}

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

,

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}

Note that:

√-1 = i

x=\frac{2\pm\sqrt[]{16\times-1}}{10}

x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}x=\frac{2\pm4i}{10}x=\frac{2}{10}\pm\frac{4i}{10}x=\frac{1}{5}\pm\frac{2}{5}ix=\frac{1\pm2i}{5}

That is;

\text{Either x=}\frac{1+2i}{5}\text{ or     x=}\frac{1-2i}{5}

7 0
1 year ago
The Punjab Highway department is studying traffic pattern on G.T. Road near Lahore. As part of previous study, population standa
Ainat [17]

Answer:

for this we need 90 percent 5410

so we multiply 5410*0.9=4869

Hope This Helps!!!

5 0
3 years ago
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