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Sergeu [11.5K]
3 years ago
7

What is the solution to the system of equations graphed below? Pls Quick

Mathematics
1 answer:
leonid [27]3 years ago
7 0
D- (-2,3) :)



hope that helps
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Help it's due in 20 minutes ​
seraphim [82]

Answer:

Its the first one | -9 | < | 9 |

Step-by-step explanation:

its false because both sides are identical

Hope this helps!

8 0
3 years ago
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Round 25.789 to the nearest tenth
Akimi4 [234]

Answer:----------->

25.8


8 0
3 years ago
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What is the solution set of {xlx&lt;-3}{xlx&gt;5)?
Anna007 [38]
<h3>Answer: C. Empty set</h3>

Explanation:

The first set {x | x < -3} means we're talking about numbers smaller than -3. This includes -4, -5, -6, etc

The second set {x | x > 5} means we're talking about numbers larger than 5. So things like 6,7,8,...

Combining both at the same time, we want to find a number that is both smaller than -3 and larger than 5. This is impossible as no such number exists. You can pick one or the other, but not both.

There are no solutions. Since there are no solutions, the solution set is the empty set.

8 0
3 years ago
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
2 years ago
What is 0.5% of 30,193,864
DerKrebs [107]

Answer:

what is 0.5% of 30 = 0.15

what is 0.5% of 193 = 0.965

what is 0.5% of 864 = 4.32

Step-by-step explanation:

6 0
2 years ago
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