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Dahasolnce [82]
3 years ago
11

How do I do sample space?

Mathematics
1 answer:
labwork [276]3 years ago
7 0
The sample space is all of the possible combinations using the stuff given. For example, you can make a ham and rye sandwich, a ham and sourdough sandwich, and a ham and white sandwich, and so on.
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How many complex roots does the polynomial equation have?<br><br> 3x5−2x+1=0
dmitriy555 [2]

Answer : The given polynomial equation can have 0,2 or 4 complex roots.

Explanation:-

Given polynomial equation is 3x^5-2x+1=0 which is a polynomial of degree 5.

We know that the complex roots always occur in pair ,therefore the number of complex roots in any polynomial must be an even number but less than equal  to the degree of polynomial.

Thus, the given polynomial equation has 4 complex roots.

3 0
4 years ago
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What are the answers to ther two questions??
Vlad1618 [11]
the answer is the third option, starting with degree 11.
6 0
3 years ago
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Need to be able to check this assignment for my son and I have no clue how to make sure it's correct anyone?
saw5 [17]

Answer:

it is correct

Step-by-step explanation:

4 0
3 years ago
Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function f(
alekssr [168]

Identify the vertex, axis of symmetry, minimum or maximum, domain, and range of the function ()=−(+)^−

<em><u>Answer:</u></em>

vertex = (-4, -5)

Axis of symmetry = -4

use the (-4, -5) to find the minimum value

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

<em><u>Solution:</u></em>

Given function is:

f(x) = (x+4)^2 - 5

The equation in vertex form is given as:

y = a(x-h)^2+k

Where, (h, k) is constant

On comparing give function with vertex form,

h = -4

k = -5

Vertex is (-4 , -5)

Axis of symmetry : x co-ordinate of vertex

Thus, axis of symmetry = -4

The coefficient of x^2 is positive in given function.

Thus the vertex point will be a minimum

Minimum\ value = f(\frac{-b}{a})

f(x) = x^2 + 8x + 16 - 5\\\\f(x) = x^2 + 8x + 11

f(x) = ax^2+bx+c

On comparing,

a = 1

b = 8

x = \frac{-b}{2a} = \frac{-8}{2 \times 1} = -4

f(-4) = (-4)^2 + 8(-4) + 11 = 16 - 32 + 11 = -5

Thus, use the (-4, -5) to find the minimum value

Domain and range

f(x) = (x+4)^2 - 5

The domain is the input values shown on the x-axis

The range is the set of possible output values f(x)

Therefore,

Domain = ( - \infty, \infty ) , [ x | x\ is\ real ]\\\\Range = [ -5, \infty ), y\geq -5

4 0
3 years ago
What is the part and whole of 40% of 20?
pashok25 [27]
The answer is 8

I hope this helps!
5 0
3 years ago
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