Saturated hydrocarbons are relatively unreactive except in the presence of _____.
2 answers:
Answer:
Saturated hydrocarbons are relatively unreactive except in the presence of high temperatures and oxygen.
Step-by-step explanation:
we have to choose the option in which saturated hydrocarbons react.
Saturated hydrocarbons do contain double and triple bonds that make molecule reactive. They only contains sigma bonds, which are very stable and difficult to break and hence these are unreactive.
In saturated hydrocarbons the percentage of carbon is lower which gets easily oxidised in oxygen of the air to form completely.
Saturated hydrocarbons are generally unreactive, but when exposed to high temperatures and oxygen they react in a combustion reaction to produce Carbon Dioxide and Water.
Hence, Saturated hydrocarbons are relatively unreactive except in the presence of high temperatures and oxygen.
Option option 1 is correct.
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Rate of change is also knkown as slope which is found by
=slope if you know 2 points/ordered pairs
aos, if x incheases while y decreases then slope is negative
when x increases while y increases then slpe if positive
also, if you can convert to y=mx+b, m=slope
another thing if you have ax+by=c then slope=-a/b
so first one
2x-5y=15
a=2
b=-5
-2/-5=2/5
slope=2/5
positive
next
y=-4x
-4 =slope=negative
x increases while y decreases
negative
x increases while y decreases
negative
so
Positive
Negative
Negative
Negative
A. 6x-3y=12
sloope=-6/-3=2
B. y=5x+b
slope=5
C. (8-2)/(3-1)=6/2=3
sloope=3
D. goes up 4 units and goes right 1 unit, 4/1=4
sloope=4
5 is greates
B is the answer
A. (6-3)/(4-3)=3/1=3
slope=3
B. y=4+6x
slope=6
C.12x+6y=18
slope=-12/6=-2
D. goes down 5 units as it goest 1 uniit to right aka -5./1
slope=-5
greatest is 6
B is answer
the starting value I would guess si when x=1 what is the greats y value
look at each
first one
A. x=1 and =-3
B.y=3x-8
y=3(1)-8
y=3-8
y=-5
C. 8x+4y=16
8(1)+4y=16
8+4y=16
4y=8
y=2
D. at 1 unit to right it is 1 nit up so y=1
greatest is 2 or C
so just subsitute 1 for x since x represents how many teaspoons
y=16(1)560
y=16+560
y=576 caloris for 1 sugar teaspoon
for honey, just read off the graph
for when x=1
y=504
so calores of sugar=576
calories in honey=504
ANSWERS
Postive
Negative
Negative
Negative
B
B
C
sugar=576
honey=504
aos, if x incheases while y decreases then slope is negative
when x increases while y increases then slpe if positive
also, if you can convert to y=mx+b, m=slope
another thing if you have ax+by=c then slope=-a/b
so first one
2x-5y=15
a=2
b=-5
-2/-5=2/5
slope=2/5
positive
next
y=-4x
-4 =slope=negative
x increases while y decreases
negative
x increases while y decreases
negative
so
Positive
Negative
Negative
Negative
A. 6x-3y=12
sloope=-6/-3=2
B. y=5x+b
slope=5
C. (8-2)/(3-1)=6/2=3
sloope=3
D. goes up 4 units and goes right 1 unit, 4/1=4
sloope=4
5 is greates
B is the answer
A. (6-3)/(4-3)=3/1=3
slope=3
B. y=4+6x
slope=6
C.12x+6y=18
slope=-12/6=-2
D. goes down 5 units as it goest 1 uniit to right aka -5./1
slope=-5
greatest is 6
B is answer
the starting value I would guess si when x=1 what is the greats y value
look at each
first one
A. x=1 and =-3
B.y=3x-8
y=3(1)-8
y=3-8
y=-5
C. 8x+4y=16
8(1)+4y=16
8+4y=16
4y=8
y=2
D. at 1 unit to right it is 1 nit up so y=1
greatest is 2 or C
so just subsitute 1 for x since x represents how many teaspoons
y=16(1)560
y=16+560
y=576 caloris for 1 sugar teaspoon
for honey, just read off the graph
for when x=1
y=504
so calores of sugar=576
calories in honey=504
ANSWERS
Postive
Negative
Negative
Negative
B
B
C
sugar=576
honey=504