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PIT_PIT [208]
2 years ago
11

Mr. Baker wants to divide his class into smaller, equal-sized groups of students.However, he finds that his class cannot be divi

ded evenly into any size group except for individual groups of 1 is the number of its class prime or compocite?
Mathematics
1 answer:
Elis [28]2 years ago
6 0

Answer:

Prime. Prime numbers can only be divided by the whole number, or one.

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Two angles are supplementary if their sum is​ 180°. the larger angle measures five degrees more than four times the measure of a
wlad13 [49]
Let x represent the smaller angle.
Let y represent the larger angle.

The problem states that the larger angle measures five degrees more than four times the measure of the smaller angle.
With this given information, we can create the following equation.

y=4x+5

Also, they a supplementary, meaning that they add up to 180. We can create another equation.

x+y=180

Since we have two linear equations and we want to find the solution, we have a system of linear equations. Let's solve this system by using the substitution method.

Substitute y=4x+5 into x+y=180

x+y=180

After substituting, you get

x+4x+5=180

Now, combine the x's

5x+5=180

Subtract both sides by 5

5x=175

Divide both sides by 5.

x=35

Now, we can solve for y using the equation x+y=180 since we know the value of x.

35+y=180

Subtract both sides by 35.

y=145

The smaller angle has a measure of 35 degrees and the larger one has a measure of 145 degrees. Have an awesome day! :)
5 0
3 years ago
What an equivalent expression for 48 + 18x
FromTheMoon [43]

Answer:

6(8+3x)

Step-by-step explanation:

48+18x

We can factor out an 6 from each term in the expression

6(8+3x)

7 0
3 years ago
Read 2 more answers
Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
2 years ago
1. Write 33% as a fraction.
Olegator [25]

Answer:

33/100

62%

0.77

0.4

9/10

8 0
2 years ago
Read 2 more answers
Which bear describes the relationship between the successive terms in the sequence shown
Fantom [35]
Idk what awser is just tryns get points
7 0
3 years ago
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