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kow [346]
3 years ago
11

Given the relation x=y4-9y2, identify the x- and y- axis intercepts

Mathematics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

The relation between x = y4 - 9y2 is that they are both unknown also that it equals 0

Step-by-step explanation:

i don't know what y and x are the only thing i know is the relation

  • Hope i could be helpful
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Midpoint of the segment between the points (−5,13) and (6,4)
Leokris [45]

Answer: (0.5,8.5)

Step-by-step explanation:

We need to use the following formula to find the Midpoint "M":

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Given the points (-5,13) and (6,4) can identify that:

x_1=-5\\x_2=6\\\\y_1=13\\y_2=4

The final step is to substitute values into the formula.

Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)

6 0
3 years ago
Read 2 more answers
if there are more students in one group than the other would it be possible to have equal proportions?
coldgirl [10]
Yes but In the bigger group each person would have less
3 0
3 years ago
A group of students formed a circle during a game. The circumference of the circle was about 43.96 feet, and the diameter of the
lara31 [8.8K]

Answer:

pi = pi

Step-by-step explanation:

Circumference = 2 * pi * r

Equation you need:

43.96 = 2 * pi * 7

43.96 = 2 * 7 * pi

43.96 / 14 = pi

pi = 3.14

5 0
3 years ago
Please answer below :-)
Serjik [45]

Answer:

B. 88.8

Step-by-step explanation:

let x represent class y

(x+71.2)/2=80   multiply each side by 2

x+71.2=160      subtract 71.2 by both sides

x=88.8

or

trial an error

replace x with each of the numbers and see if it plugs in.

example:

(80.5+71.2)/2=80

151.7/2=80

75.85=80?

false. incorrect

another example:

(88.8+71.2)/2=80

160/2=80

80=80?

true. correct

7 0
3 years ago
Write an expression for the perimeter of the triangle shown below:
salantis [7]
P = 3x + 0.5x + 9 - 3.4x - 25
P = 0.1x - 16

answer
<span>0.1x − 16</span>
5 0
4 years ago
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