Using row 4:
<span>coefficients are: 1, 4, 6, 4, 1 </span>
<span>a^4 + a^3b + a^2b^2 + ab^3 + b^4 </span>
<span>Now adding the coefficients: </span>
<span>1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 </span>
<span>Substitute a and b: </span>
<span>a = 4x </span>
<span>
b = -3y </span>
<span>1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 </span>
<span>Now simplify the above: </span>
<span>256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4 </span>
Answer:

Step-by-step explanation:
*Missing Part of the Question*
4 stars
5 triangles
3 circles
3 squares
Required
Determine the probability of triangle being first then square being second


Represent the triangle with T and square with S
So, we're solving for P(T n S)

Solving for P(T)


Solving for P(S)
The question implies a probability without replacement;
Hence Total has now been reduced by 1
Total = 14


Recall that




Hence, the required probability is

Answer:
243 or 3^5
Step-by-step explanation:
You can do the product by multiplying starting from the left.
3 * 3 * 3 * 3 * 3 =
= 9 * 3 * 3 * 3
= 27 * 3 * 3
= 81 * 3
= 243
You can also change it to an exponential form.
3 * 3 * 3 * 3 * 3 = 3^5
Answer:
see explanation
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 4)² + (y + 6)² = 16 is in this form
with r² = 16 ⇒ r =
= 4
---------------------------------------------------------------
given (h, k) = (5, 2) and r = 20, then
(x - 5)² + (y - 2)² = 400 ← represents the delivery area
Answer:
11x-5
Step-by-step explanation: