You gotta put more information out buddy
We can use the distributive property to set up an expression that is equal to this problem.
14 times 8 is 112
14 times -6 is -84x
14 times 12 is 168
(If you don't know the distributive property ask and I can explain it)
We can combine that together to get:
112 +168 -84x
Or, condense it further:
280-84x is equivalent to 14(8-6x+12)
Answer: $7
Step by step explanation: so first, we have to form any equation to show that some amount of money was added to eight dollars to get a total of fifteen dollars. Our equation becomes 8+x=15
Where eight is the origins amount, x is the amount that's added to the original amount and fifteen is the final amount.
We then move eight to the other side as a negative number
x=15-8
Therefore, x is equal to seven dollars.
Answer:
Option 4
Step-by-step explanation:
Term = n/(4^n)
(n+1)th term = (n+1)/[4^(n+1)]
Ratio: (n+1)/[4^(n+1)] ÷ n/(4^n)
= (n+1)/[4^(n+1)] × (4^n)/n
= [(n+1)/n] × (1/4)
For large n, (n+1)/n approaches 1
[(n+1)/n] × (1/4) approaches 1/4 which is less than 1
Since the ratio is less than 1, series converges
Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
