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2 years ago

8

A pan of brownies is 7/10 full. Tyreese buys 2/5 of the brownies. What fraction of a whole pan of brownies does Tyreese buy?

1 answer:

Nady [450]2 years ago

5 0

2/5 of 7/10 =7/25 of the whole pan

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

2 years ago

Solve and round the answer to the nearest hundredths plz helpppp

Kaylis [27]

Answer:

696.91

Step-by-step explanation:

$V = \frac{4}{3} *\pi *r^3\\= \frac{4}{3}*\pi *5.5^3\\= \frac{4}{3}*\pi *166.375\\=696.9099703\\$

≈ 696.91

7 0

3 years ago

What is the solution to this equation?

pychu [463]

Answer:

A. x = 3

Step-by-step explanation:

5x+15 + 2x = 24 +4x

7x+15=24+4x

7x+15-15=24+4x-15

7x=4x+9

7x-4x=4x+9-4x

3x=9

3x/3=9/3

x=3

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1 year ago

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Which of the following is the value of pq ? 2x+41

loris [4]

m pq = 2 Have a good day! sorrey if i'm wrong

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2 years ago

Herman and Helga had a combined gross income of $391,200 in 2009. When filing their federal income tax return with the Married F

viva [34]

33% depending on if your numbers is the same as mine

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3 years ago

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