Question

Perform the indicated operations. Do the root of -48 in terms of i please

Answer 1

Answer:

$\frac{-5-\sqrt{-48}}{40}$  in terms of i is: $\frac{-1}{8}-\frac{i\,\sqrt{3}}{10}$

Step-by-step explanation:

$\frac{-5-\sqrt{-48}}{40}$

We know that $\sqrt{-1} = i$

so,

$\frac{-5-\sqrt{48}i}{40}$

Now solving:

$=\frac{-5}{40}-\frac{i\,\sqrt{48}}{40}\\=\frac{-1}{8}-\frac{i\,\sqrt{2*2*2*2*3}}{40}\\=\frac{-1}{8}-\frac{i\,\sqrt{2^2*2^2*3}}{40}\\=\frac{-1}{8}-\frac{2*2\,i\,\sqrt{3}}{40}\\=\frac{-1}{8}-\frac{4\,i\,\sqrt{3}}{40}\\=\frac{-1}{8}-\frac{i\,\sqrt{3}}{10}$

So, $\frac{-5-\sqrt{-48}}{40}$  in terms of i is: $\frac{-1}{8}-\frac{i\,\sqrt{3}}{10}$